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Katyanochek1 [597]
3 years ago
13

What will be the cost of gasoline for a 4,700-mile automobile trip if the car gets 41 miles per gallon, and the average price of

gas is $3.79 per gallon?
Chemistry
2 answers:
Marrrta [24]3 years ago
8 0

Answer:

Idk

Explanation:

Find the gallons needed by dividing total miles by miles per gallon:

4700/41 = 114.634 gallons

Multiply the gallons needed by price per gallon:

114.634 x 2.79 = $319.83 Total

Round the answer as needed.

If gallons were rounded to 115 gallons total cost would be $320.85

NARA [144]3 years ago
3 0
  • Answer:

<em> $ 434.40</em>

  • Explanation:

<em>41 miles ............ 1 gallon</em>

<em>4700 miles .......x gallon</em>

<em>x = 4700×1/41 = 114.63 gallons</em>

<em />

<em>114.63 gallons×$3.79 ≈  $ 434.40</em>

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Cuantos moles de CO2 se requieren para reaccionar con 2 moles de Ba (OH)2
EastWind [94]

Answer:

hola soy jess, tu respuesta esta aqui

¿cuantos moles de CO2 se requiere para reaccionar 2 moles de Ba(OH)2

2 mol Ba(OH)₂ × \frac{1molCO_{2} }{1molBa (OH)_{2}}

1molBa(OH)

2

1molCO

2

= 2 moles CO₂

Explanation:

espero que pueda ayudarte

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3 0
3 years ago
Two students made the Lewis dot diagrams of H2O. The diagrams are as shown.
netineya [11]

Answer:

Only student A

Explanation:

don’t worry I got a 100

7 0
3 years ago
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You decide you want to carry a boulder home from the beach. It is 20 centimeters on each
e-lub [12.9K]

Answer:

Weight of boulder = 22,400 gram

Explanation:

Given:

Volume = 8,000 cm³

Density = 2.8

Find:

Weight of boulder

Computation:

Weight of boulder = Volume x Density

Weight of boulder = 8,000 x 2.8

Weight of boulder = 22,400 gram

3 0
3 years ago
The combustion of palmitic acid is represented by the chemical equation: C16H32O2(s) + 23O2(g) → 16 CO2(g) + 16 H2O(l) The magni
solniwko [45]

Answer:

The correct option is C

Explanation:

From the question we are told that

The reaction is

C_{16}H_{32}O_2(g) + 23O_2(g) \to 16 CO_2(g) + 16 H_2O(l)

Generally \Delta  H  =  \Delta  U + \Delta N*  RT

Here \Delta  H is the change in enthalpy

\Delta  U is the change in the internal energy

              \Delta N  is the difference between that number of moles of product and the number of moles of reactant

Looking at the reaction we can discover that the elements that was consumed and the element that was formed is O_2 and  CO_2 and this are both gases so the change would occur in the number of moles

So  

\Delta  H  =  \Delta  U + [16 -23]*  RT

\Delta  H  =  \Delta  U -7RT

The  negative sign in the equation tell us that the enthalpy\Delta_r H would be less than the Internal energy \Delta_r U

4 0
3 years ago
Determine the acid dissociation constant for a 0.0250 M weak acid solution that has a pH of 2.37 . The equilibrium equation of i
Oksanka [162]

Answer:

For part (a): pHsol=2.22

Explanation:

I will show you how to solve part (a), so that you can use this example to solve part (b) on your own.

So, you're dealing with formic acid, HCOOH, a weak acid that does not dissociate completely in aqueous solution. This means that an equilibrium will be established between the unionized and ionized forms of the acid.

You can use an ICE table and the initial concentration ofthe acid to determine the concentrations of the conjugate base and of the hydronium ions tha are produced when the acid ionizes

HCOOH(aq]+H2O(l]⇌ HCOO−(aq] + H3O+(aq]

I 0.20 0 0

C (−x) (+x) (+x)

E (0.20−x) x x

You need to use the acid's pKa to determine its acid dissociation constant, Ka, which is equal to

3 0
2 years ago
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