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3 years ago

What are the possible values that probability can have?

Mathematics

1 answer:

mojhsa [17]3 years ago

6 0

The possible values that a probability can have ranges from 0 to 1 inclusive.

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Solve p=10a+3b for a

Gre4nikov [31]

Answer:

a = (p - 3b)/10

Step-by-step explanation:

Isolate the variable, a. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS (Parenthesis, Exponents (& roots), Multiplication, Division, Addition, Subtraction).

p = 10a + 3b

First, subtract 3b from both sides.

p (-3b) = 10a + 3b (-3b)

p - 3b = 10a

Next, isolate the a. Divide 10 from both sides.

(p - 3b)/10 = (10a)/10

(p - 3b)/10 = a

a = (p - 3b)/10 is your answer.

5 0

3 years ago

HELP ASAP!!! 40 POINTS

ICE Princess25 [194]

Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:

(-15,-10).

<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>

It is given by the derivative at x = x0, that is:

$m = f^{\prime}(x_0)$ .

In this problem, the function is:

$f(x) = 0.2x^2 + 5x - 12$

Hence the derivative is:

$f^{\prime}(x) = 0.4x + 5$

For a slope of -1, we have that:

0.4x + 5 = -1

0.4x = -6

x = -15.

For a slope of 1, we have that:

0.4x + 5 = 1.

0.4x = -4

x = -10

Hence the interval is:

(-15,-10).

More can be learned about derivatives and tangent lines at brainly.com/question/8174665

#SPJ1

8 0

2 years ago

A cable is 84 meters long, it is cut into two pieces so that one piece is 18 meters longer than the other. Find the length of ea

weeeeeb [17]

Long Piece: x + 18

Short Piece: x

(x) + (x + 18) = 84

2x + 18 = 84

2x = 66

x = 33

Long Piece: x + 18 = (33) + 18 = 51

Answer: 33 meters and 51 meters

5 0

3 years ago

A quantity x has cumulative distribution function p(x) = x − x2/4 for 0 ≤ x ≤ 2 and p(x) = 0 for x < 0 and p(x) = 1 for x &gt

34kurt

$F_X(x)=\begin{cases}0&\text{for }x2\end{cases}$

Recall that the PDF is given by the derivative of the CDF:

$f_X(x)=\dfrac{\mathrm dF_X(x)}{\mathrm dx}=\begin{cases}1-\dfrac x2\\\\0&\text{otherwise}\end{cases}$

The mean is given by

$\mathbb E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\int_0^2\left(x-\dfrac{x^2}2\right)\,\mathrm dx=\frac23$

The median is the number $M$ such that $F_X(x)=\mathbb P(X\le M)=\dfrac12$ . We have

$F_X(M)=M-\dfrac{M^2}4=\dfrac12\implies M=2\pm\sqrt2$

but both roots can't be medians. As a matter of fact, the median must satisfy $0\le M\le2$ , so we take the solution with the negative root. So $M=2-\sqrt2$ is the median.

3 0

3 years ago

The school store has 750 packs of crayons.each pack has 12 markers in it.how many markers are there in all

kirza4 [7]

There are 9,000 markers in total

750 x 12 = 9,000

3 0

3 years ago