Answer:
10 cuadrados
Step-by-step explanation:
Si uno de los lados de rectangulo es de 4cm entonces el lado parallelo tambien es de 4cm. Eso nos da 8cm del perimetro y nos quedan los otros dos lados que tienen la misma medida. Entonces dividimos el resto del perimetro por 2.
28 - 8 = 20cm
20cm / 2cm = 10cm
Ahora que tenemos todas las medidas podemos multiplicar el largo por el ancho para calcular el area del rectangulo
10cm * 4cm = 40
el cuadrado de 2cm tendra un area de
2cm * 2cm = 4
Ahora simplemente dividimos el area del rectangulo por el area del cuadrado para saber cuantos cuadrados necesitamos para armar ese rectangulo
40 / 4 = 10 cuadrados
Factors of 35: 1, 5, 7, 35
Of those, only 5 and 7 are prime.
7>5
Final answer: 7
Answer:
A. (y+z=6) -8
Step-by-step explanation:
You will use the process of adding together the like terms. Since in equation Q, we have 8y, we need -8y in equation P. Answer A is the only one that will give us -8. You have to distribute -8 across all the variables and numbers in the parenthesis.
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
