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Gnoma [55]
3 years ago
11

Compare the occurrence of heavier elements on earth and the universe.

Chemistry
1 answer:
k0ka [10]3 years ago
3 0
By definition, a heavy element is a specific kind of element with a larger atomic mass. An element could be considered as "heavy" if its atomic number is greater already than 92. One of the known heavy elements on Earth is Tennessine and Tungsten while in the universe are lithium-5 and berryllium-8.
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What is rate a of reaction
kicyunya [14]
The rate of the reaction is measurable quantity that refers to the amount or how much is are chemical substances reagents used up or converted into the product over some period of time.

Rate = change in the amount/time.

This can indirectly be observed through many ways, such as the volume of gas given off if the byproduct is a gas being produced, the colour of the solution etc.
4 0
3 years ago
Which of the following best describes exothermic chemical reactions?<br>​
zlopas [31]
They always release heat
3 0
4 years ago
Choose the correct statement regarding the relative size of atoms:
Sonbull [250]

Answer:

The atoms on left side are larger than the atoms on the right side of the periodic table because those on the right have more proton's.

Explanation:

As we travel along a period in a periodic table then the atomic radii decreases

This is because as we travel along a period we have that the atomic number of the atoms increases which means the the number of proton's increased

But the electron's add to the same outer shell throughout the period , which means the effective nuclear charge increases which pulls the outer electrons toward's the nucleus and the size decreases.

Therefore the atoms on left side are larger than the atoms on the right side of the periodic table because those on the right have more proton's.

6 0
3 years ago
A gas absorbs 10J of heat and is simulataneously comptessed by a constant external pressure of 0.5atm from 4L to2L in volume.Wha
Ne4ueva [31]

Answer:

B. 111 J

Explanation:

The change in internal energy is the sum of the heat absorbed and the work done on the system:

ΔU = Q + W

At constant pressure, work is:

W = P ΔV

Given:

P = 0.5 atm = 50662.5 Pa

ΔV = 4 L − 2L = 2 L = 0.002 m³

Plugging in:

W = (50662.5 Pa) (0.002 m³)

W = 101.325 J

Therefore:

ΔU = 10 J + 101.325 J

ΔU = 111.325 J

Rounded to three significant figures, the change in internal energy is 111 J.

7 0
3 years ago
What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom
Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains 6.022\times 10^{23} atoms

So, 5.5 g of lead contains \frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22} atoms

and,

As, 118.71 g of lead contains 6.022\times 10^{23} atoms

So, 94.5 g of lead contains \frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23} atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%

and,

\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

6 0
3 years ago
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