HCl ----------> H(+) + Cl(-)
0,0045-x.........x...........x
0..................0,0045...0,0045
pH = -log[H+]
pH = -log[0,0045]
pH = 2,347
pOH = 14-pH
pOH = 14-2,347
pOH = 11,653
pOH = -log[OH-]
[OH-] = 10^-pOH
[OH-] = 10^-11,653
[OH-] = 2,2233·10^-12 mol/dm³
Answer:
1. 315.4 K
2. 1560 °C
Explanation:
To convert from celsius to Kelvin, the following formula can be used:
T(K) = T(°C) + 273
Where:
T(K) => Temperature in Kelvin
T(°C) => Temperature in degree celsius
1. Determination of the temperature in Kelvin.
Temperature (T) in °C = 42.4 °C.
Temperature (T) in K =?
T(K) = T(°C) + 273
T(K) = 42.4 °C + 273
T(K) = 315.4 K
2. Determination of the temperature in degree Celsius.
Temperature (T) in K = 1833 K
Temperature (T) in °C =?
T(K) = T(°C) + 273
1833 = T(°C) + 273
Collect like terms
T(°C) = 1833 – 273
T(°C) = 1560 °C
This example is an controversial matter because melting an candle is considered as both physical change and chemical change because no new substances were made by melting an candle. The final answer is C.
5 moles of H2
..............
Answer:
Explanation:
To find the weight (W) of the pond contents first we need to use the following equation:
(1)
Where m the mass and g is the gravity
Also, we have that the mass is:
(2)
Where ρ is the density and V the volume
We cand calculate the volume as follows:
(3)
Where L is the length, w is the wide and d is the depth
By entering equation (2) and (3) into (1) we have:
Therefore, the weight of the pond is 6.65x10⁶ lbf.
I hope it helps you!
