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Gnoma [55]
3 years ago
11

Compare the occurrence of heavier elements on earth and the universe.

Chemistry
1 answer:
k0ka [10]3 years ago
3 0
By definition, a heavy element is a specific kind of element with a larger atomic mass. An element could be considered as "heavy" if its atomic number is greater already than 92. One of the known heavy elements on Earth is Tennessine and Tungsten while in the universe are lithium-5 and berryllium-8.
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Using stoichiometry, you predict that you should be able to use 314.0 g of Al to produce 1551 g of AlCi3. In your lab
Alex787 [66]

Answer:

90.26%

Explanation:

From the question given above, the following data were obtained:

Theoretical yield of AlCl₃ = 1551 g

Actual yield of AlCl₃ = 1400 g

Percentage yield =?

The percentage yield of the reaction can be obtained as follow:

Percentage yield = Actual yield / Theoretical yield × 100

Percentage yield = 1400 / 1551 × 100

Percentage yield = 140000 / 1551

Percentage yield = 90.26%

Thus, the percentage yield of the reaction is 90.26%

6 0
3 years ago
What are conversion factors in chemistry?
jenyasd209 [6]
A conversion factor is ALWAYS equal to 1 :)
5 0
3 years ago
hydrogen gas and oxygen gas react to form liquid hydrogen peroxide. which starement is true about the reaction?
Strike441 [17]
The two elements mixed together to form a chemical bond and reacted as a chemical change
4 0
3 years ago
The volume of a given mass of agas is 360cm cubic at 50 degrees and 700 milimetres Hg .find it's volume at s.t.p​
saveliy_v [14]

Answer:

V₂  =279.9 cm³

Explanation:

Given data:

Initial volume = 360 cm³

Initial temperature = 50°C

Initial pressure = 700 mmHg

Final volume = ?

Final temperature = 273 k

Final pressure = 1 atm

Solution:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Solution:

<em>We will convert the mmHg to atm.</em>

700/760 = 0.92 atm

<em>and °C to kelvin.</em>

50+273 = 323 K

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 0.92 atm × 360 cm³ × 273 K / 323 K ×1 atm

V₂  =  290417.6 atm .cm³.  K  / 323 k. atm

V₂  =279.9 cm³

8 0
3 years ago
Which conversion factor correctly shows the relationship between moles and representative particles?
strojnjashka [21]
This is given by Avogagro number: 1 mol = 6.02*10^23 particles

Then you can do whichever to these two relations, because they are equivalent:

- 1mol / 6.02*10^23 representative particles, and
- 6.02*10^23 representative particle /1 mol

Only the second option of the question includes one of the valid conversion factors. Then, the conversion factor of the second option is the right answer
8 0
3 years ago
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