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Zanzabum
3 years ago
14

Identify the factor terms by grouping: 4x^3 + 2x^2 – 18x – 9

Mathematics
2 answers:
Rainbow [258]3 years ago
8 0

Answer:

C) 2x^2(2x + 1) - 9(2x + 1)

Step-by-step explanation:

hram777 [196]3 years ago
5 0
Group terms that have factorable coefficients (like 2&4 and then 9&18)

(4x³ + 2x²) + (-18x - 9)

factor out the like terms
2x²(2x + 1) - 9(2x +1)

parenthesis are the same so you can factor further.. {Like 2x+3x = (2+3)x}

(2x² - 9)(2x+1)

Factored too far they only want Answer C. is the correct one for grouping
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The actual length of Wall C is 4 m. To represent Wall C, Noah draws a segment 16 cm long. What scale is he using?
hjlf

Answer:

\frac{1m}{4cm}

Step-by-step explanation:

First write the problem out as a fraction.

\frac{4}{16}

Next see if there is a GCF

4:1,2,4

16:1,2,4,8,16

Finally divide the numerator and denomenator by the GCF

\frac{4}{16} /4=\frac{1}{4}

4 0
3 years ago
What is the value of x?
Nikolay [14]
Answer: 7 centimeters 

Explanation:

Let triangle ABC and triangle CDE form a bow tie such that 
     - triangle ABC is smaller than triangle CDE
     - Segment AC and segment CD are the north sides
     - Segment BC and segment CE are the bottom sides
     - AC = 6, CD = 42, CE = 36, BC = x

Since angle ACB and angle ECD are formed by intersecting segment AE and segment BD at point C, they are vertical angles. (See the attached picture) So, angle ACB and angle ECD are congruent. 

Moreover when we form our bowtie, point A is in the north side and point E is in the bottom sides and this implies that angle BAC and angle CED are alternate interior angles as shown in the attached figure. 

Since it is given in the problem that alternating interior angle are congruent, angle BAC and angle CED are congruent. 

Now, we have the following pairs of angles in triangle ABC and triangle CDE that are congruent:

- angle BAC and angle CED
- angle ACB and angle ECD

By AA Similarity theorem, when we have two pairs of congruent angles for two triangles, then the two triangles are similar. So, triangle ABC and triangle CDE are similar.

In similar triangles, the sides that are opposite to the congruent angles are proportional to each other. So, 

\frac{BC}{CD}  =  \frac{AC}{CE} 


    (1)

Since AC = 6, CD = 42, CE = 36, BC = x, we can substitute these values to equation (1). So, equation (1) becomes

\frac{x}{42} = \frac{6}{36}
\frac{x}{42} = \frac{1}{6}  (2)

SInce we are solving for x, we can multiply both sides of equation (2) by the denominator at the left side which is 42 so that

x = 42(1/6)
x = 7 centimeters

8 0
3 years ago
Need help on question 4??
Anit [1.1K]

HK consists of two part, HJ and JK

HK = HJ + JK

We know that:

HK = 12.2ft

JK = 3.1ft

HJ = ?

Let's plug our values into the equation above.

12.2ft = HJ + 3.1ft

Subtract 3.1ft from both sides.

9.1ft = HJ

4 0
3 years ago
Number of heads: 0,1,2,3 Frequency: 16,38,34,12 Find the median​
zubka84 [21]

Answer:

the median of 0 1 2 3 16 38 34 12 is 9.5

8 0
3 years ago
The larger of two numbers is 15 more than three times the smaller number. If the sum of the two
aivan3 [116]

Step-by-step explanation:

Let the smaller number be x

Greater number = 3x + 15

3x + 15 + x = 63

4x + 15 = 63

4x = 63 - 15

4x = 48

x = 48/4

x = 12

Greater number = 3(12) + 15 = 51

7 0
3 years ago
Read 2 more answers
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