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SCORPION-xisa [38]
3 years ago
10

Mars is 7AU from earth, what is that in mm

Chemistry
1 answer:
aniked [119]3 years ago
6 0

7AU = 1 × 10^15 mm

7AU × (1.5 ×10^8 km/1 AU) = 1.0 × 10^9 km

1.0 × 10^9 km × (1000 m/1 km) = 1.0 × 10^12 m

1.0 × 10^12 m × (1000 mm/1m) = 1 × 10^15 mm

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PLEASE HELP ME THIS IS DUE RN I HAVE NO IDEA I WILL MARK BRAINLIEST I JUST NEED HELP
djverab [1.8K]

Answer:

3.45 × 10^5

=3.45^5

I hope this helps

6 0
3 years ago
Worth many points (timed test)
ANEK [815]

Answer:

2.335 J/g*degrees celcius

Explanation:

6 0
3 years ago
List a mixture that can be separated by fractional distillation
vivado [14]
Separation of components of crude oil
5 0
3 years ago
. How many grams of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide? ____Cl
dlinn [17]

Answer: 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide.

Explanation:

The balanced chemical reaction is;

Cl_2+MgBr_2\rightarrow MgCl_2+Br_2

Cl_2 is the limiting reagent as it limits the formation of product and MgBr_2 is the excess reagent.

According to stoichiometry :

1 mole of Cl_2 produces = 1 mole of MgCl_2

Thus 2 moles of Cl_2 will produce=\frac{1}{1}\times 2=2moles  of MgCl_2

 Mass of MgCl_2=moles\times {\text {Molar mass}}=2moles\times 95g/mol=190g

Thus 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide

5 0
2 years ago
Calcium carbide, CaC2, is manufactured by reducing lime with carbon at high temperature. (The carbide is used in turn to make ac
sweet-ann [11.9K]

The energy of the carbide released is 7262.5MJ.

<h3>What is the energy?</h3>

We know that the reaction between calcium  oxide and carbon occurs in accordance with the reaction; CaO(s)+3C(s)----- > CaC_{2} (s)+CO(g). The reaction is seen to produce 464.8kJ of energy per mole of carbide produced.

Number of moles of CaC_{2} produced = 1000 * 10^3 g/64 g/mol

= 15625 moles of calcium carbide

If 1 mole of CaC_{2} transfers  464.8 * 10^3 J

15625 moles of calcium carbide transfers 15625 moles  * 464.8 * 10^3 J/ 1 mol

= 7262.5MJ

Learn more about reaction enthalpy:brainly.com/question/1657608

#SPJ1

7 0
1 year ago
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