Answer:
YIkES One thing u can do i ask your teacher about it or say that u need help with it the cant make fun of u because u need help with your work.
Answer:
I'm pretty sure its C. limestone.
Shorter because the I-I bond in the I2 molecule is covalent whereas the bond between adjacent molecules is due to dispersion.
<h3>What is bond length?</h3>
Bond length typically falls between 0.1 and 0.2 nm. Covalent radius is the term used to describe the length of a connection formed between two comparable atoms. The order of the bond or the quantity of linked electrons between two atoms determines the bond length.
<h3>
What connection exists between the length and the strength of a bond?</h3>
The C-C bond in alkanes must be the longest since it is the weakest, and the C-C bond in alkynes must be the shortest because it appears to be the strongest, according to the data. We determined in the preceding section that the bond strength is inversely correlated to the bond length.
<h3>How can bond length be calculated in chemistry?</h3>
- The bond gets shorter as the atoms get smaller.
- The length of the bond decreases as bond multiplicity increases.
- The shorter the bond, the higher the effective nuclear charges of the bound atoms.
Learn more about bond length:
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Answer:
Decreases
Explanation:
The atmospheric pressure on the surface of the mercury pushes it up the evacuated tube until the downward pressure of the mercury equals the atmospheric pressure.
If the atmospheric pressure decreases, the mercury doesn't have to rise as high.
The mercury height decreases.
Answer:
5.13×¹⁴ Hz
Explanation:
The following data were obtained from the question:
Energy (E) = 3.4×10¯¹⁹J
Frequency (f) =?
Energy and frequency are related by the following formula:
E = hf
Where:
E is the energy.
h is the Planck's constant.
f is the frequency.
Thus, we can obtain the frequency of the photon by using the above formula as illustrated below:
Energy (E) = 3.4×10¯¹⁹J
Planck's constant (h) = 6.63×10¯³⁴ Js
Frequency (f) =?
E = hf
3.4×10¯¹⁹ = 6.63×10¯³⁴ × f
Divide both side by 6.63×10¯³⁴
f = 3.4×10¯¹⁹ / 6.63×10¯³⁴
F = 5.13×¹⁴ Hz
Thus, the frequency of the photon is 5.13×¹⁴ Hz.