Answer:
5.13 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 5.33 L
Initial temperature (T₁) = 21 °C
Final temperature (T₂) = 10 °C
Final volume (V₂) =?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 21 °C
Initial temperature (T₁) = 21 °C + 273
Initial temperature (T₁) = 294 K
Final temperature (T₂) = 10 °C
Final temperature (T₂) = 10 °C + 273
Final temperature (T₂) = 283 K
Finally, we shall determine the final volume. This can be obtained as follow:
Initial volume (V₁) = 5.33 L
Initial temperature (T₁) = 294 K
Final temperature (T₂) = 283 K
Final volume (V₂) =?
V₁/T₁ = V₂/T₂
5.33 / 294 = V₂ / 283
Cross multiply
294 × V₂ = 5.33 × 283
294 × V₂ = 1508.39
Divide both side by 294
V₂ = 1508.39 / 294
V₂ = 5.13 L
Thus, the new volume of the football is 5.13 L
