Answer:
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Explanation:
1.506 × 10²³ carbon atoms
Explanation:
First we calculate the number of moles of calcium carbonate (CaCO₃) contained in 25 g.
number of moles = mass / molecular weight
number of moles of CaCO₃ = 25 / 100 = 0.25 moles
Now we make use of Avogadro's number which tell us that we have 6.022 × 10²³ molecules (or atoms) in one mole of substance.
Now in our case:
if in 1 mole of CaCO₃ we have 1 × 6.022 × 10²³ carbon atoms
then in 0.25 moles of CaCO₃ we have X carbon atoms
X = (0.25 × 1 × 6.022 × 10²³) / 1
X = 1.506 × 10²³ carbon atoms
Learn more:
Avogadro's number
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2NaCN(s) + H₂SO₄(aq) --> Na₂SO₄(aq) + 2HCN(g)
The molar ratio between NaCN : HCN is 2:2 or 1:1
Mass of HCN = 16.7 g
Molar mass of HCN = 1 + 12 + 14 = 27 g/mol
Molar mass of NaCN = 49 g/mol
Therefore, the mass of NaCN is
16.7 g of HCN x 49 g/mol of NaCN / 27 g/mol of HCN = 30.3 grams of NaCN
Therefore, 30.3 grams of NaCN gives the lethal dose in the room.
There are two big advantages of using molarity to express concentration. The first advantage is that it's easy and convenient to use because the solute may be measured in grams, converted into moles, and mixed with a volume.
The second advantage is that the sum of the molar concentrations is the total molar concentration. This permits calculations of density and ionic strength
Answer:
The hydrogen bond between hydrogen fluoride molecules is stronger because the polarization in H-F molecule is stronger.
Explanation:
The more polarization happens in the molecule the stronger the inter-molecular hydrogen bond is.
Consider water (H - O - H) and hydrogen fluoride (H - F), the polarization of the (H - F) bond is stronger than the (O - H) bond due to the higher electronegativity of the fluoride atom. Actually, fluoride has the highest electronegativity.