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Paha777 [63]
3 years ago
12

Calcium oxide and oxygen gas are produced by the thermal decomposition of limestone in the reaction CaCO (s) CaO(s) + CO (g). Wh

at mass of lime can be produced from 4.5 10 kg of limestone? Please show all the work
Chemistry
2 answers:
kozerog [31]3 years ago
6 0
The mass of lime that  can  be produced  from  4.510 Kg of limestone  is calculated  as  below

calculate the moles  of CaCO3  used

that is  moles =mass/molar mass
convert  Kg  to g  = 4.510 x1000 =4510g
=  4510 / 100 =45.10 moles
CaCO3 = CaO  +O2

by use of mole ratio between CaCO3  to CaO  (1:1) the  moles of CaO  is also= 45.10 moles
mass of CaO = moles x molar  mass

45.10  x56 = 2525.6  g  of  CaO



lutik1710 [3]3 years ago
6 0
As the power on mass of CaCO₃ is not given so we are assuming it 4.5 × 10³ Kg.

Answer:
             2520 Kg of CaO

Solution:
 
The balance chemical equation is as follow,

                                      CaCO₃    →    CaO  + CO₂

According to equation,

           0.1 Kg (1 mole) CaCO₃ produces  =  0.056 Kg (1 mole)  of CaO
So,
            4.5 × 10³ Kg CaCO₃ will produce  =  X Kg of CaO

Solving for X,
                     X  =  (4.5 × 10³ Kg × 0.056 Kg) ÷ 0.1 Kg

                     X  =  2520 Kg of CaO
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What is the mole fraction, X, of solute and the molality, m (or b), for an aqueous solution that is 15.0% NaOH by mass?
GalinKa [24]
Hello!

a) The mole fraction of solute of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams of water. We can calculate the number of moles of each one in the following way:

molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH \\ \\ moles H_2O=85 gH_2O* \frac{1 mol H_2O}{18 g H_2O}=4,7222 moles H_2O

To finish, we calculate the mole fraction by dividing the moles of NaOH between the total moles:

X_{NaOH}= \frac{moles NaOH}{total moles}= \frac{0,3750 moles NaOH}{0,3750 moles NaOH+4,7222 molesH_2O} =0,073

So, the mole fraction of NaOH is 0,073

b) The molality (moles NaOH/ kg of solvent) of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams (0,085 kg) of water. We can calculate the moles of NaOH in the following way:

molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH

Now, we apply the definition of molality to calculate the molality of the solution:

mNaOH= \frac{moles NaOH}{kg_{solvent}}=  \frac{0,3750 moles NaOH}{0,085 kg H_2O}=4,41 m

So, the molality of this solution is 4,41 m

Have a nice day!
4 0
3 years ago
Perform the following conversion: (plz show work)<br> 1.31km = _______m
PilotLPTM [1.2K]
If this is meters, then it’d be 1310.

1km = 1000m

.31 x 1000 = 310

So, 1000 + 310 = 1310m
6 0
2 years ago
A gas occupies 3.60 L when the temperature is 45.0oC and at 1.02 atm of pressure. What temperature change (in K) will be needed
dedylja [7]
As we know V1/T1=V2/T2
so,   V1=3.60
        V2=6.25
        T1=45c=318k
        T2=required
solution!
            T2=V2 multiply by T1/V1 so
   put the values and find your answer which should be 552k
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3 years ago
HELP ASAP!! What happens to the value of K when pressure increases??
Diano4ka-milaya [45]
The value turns into P

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GarryVolchara [31]
4 moles i believe cos mole = mass/ molar mass
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3 0
2 years ago
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