What happens to the distance between interference fringes if the separation between two slits is increased?
1 answer:
Answer:
It will decrease
Explanation:
The double-slit interference equation, which gives us the position y of a maximum on the screen (measured relative to the central position), is
where
n is the order of the maximum
D is the distance between the slits and the screen
is the wavelength of the light
d is the separation between the two slits
From the formula, we see that y is inversely proportional to d: this means that if the separation between the slits is increased, the distance of each maximum from the central position (y) decreases, therefore the distance between the interference fringes will decrease.
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Answer:
A=50mΩ
B≅50mΩ
Explanation:
A) To answer this question we have to use the Current Divider Rule. that rule says:
(1)
Itotal represents the new maximun current, 50mA, Ix is the current going through the 100 ohms resistor, and Req. is the equivalent resitor.
We now have a set of two resistor in parallel, so:
(2)
where R1 is the resitor we have to calculate, and R2 is the 100 ohms resistor (25 uA).
substituting and rearranging (2)
(3)
Now substituting (3) in (1).
solving this, The value of R1 is: 50mΩ
This value of R1 will guaranty that the ammeter full reflection willl be at 50mA.
Given that R2 (100ohm) it too much bigger than 50mΩ, the equivalent resistor will tend to 50mΩ
If you substitude this values on (2) Req. will be 49.97 mΩ.