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3 years ago

9

What happens to the distance between interference fringes if the separation between two slits is increased?

1 answer:

kolezko [41]3 years ago

3 0

Answer:

It will decrease

Explanation:

The double-slit interference equation, which gives us the position y of a maximum on the screen (measured relative to the central position), is

$y=\frac{n\lambda D}{d}$

where

n is the order of the maximum

D is the distance between the slits and the screen

$\lambda$ is the wavelength of the light

d is the separation between the two slits

From the formula, we see that y is inversely proportional to d: this means that if the separation between the slits is increased, the distance of each maximum from the central position (y) decreases, therefore the distance between the interference fringes will decrease.

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The product is the what you start with in a chemical reaction

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What is the mass of a 5000 N car on Earth?

puteri [66]

Answer:

510.2kg

Explanation:

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3 years ago

Fifteen identical particles have various speeds: one has a speed of 2.00 m/s, two have speeds of 3.00 m/s, three have speeds of

Evgesh-ka [11]

Answer:

a) $V=7.5m/s$

b) $rms=8.4m/s$

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Explanation:

From the question we are told that:

Sample size N=15

$Speed 1 v_1=2m/s\\\\Speed 2 v_2=3m/s\\\\Speed 3 v_2=5m/s\\\\Speed 4 v_4=8m/s\\\\Speed 3 v_5=9m/s\\\\Speed 2 v_6=15m/s\\\\$

Generally the equation for Average speed is mathematically given by

$V_{avg}=\frac{\sum(nv)}{N}$

Therefore

$V_{avg}=\frac{(2+2(3)+3(5)+4(8)+3(9)+2(15))}{15}$

$V=7.5m/s$

b)

Generally the equation for RMS speed of the particle is mathematically given by

$rms=\sqrt{\frac{\sum(nv^2)}{N}}$

$rms=\sqrt{\frac{2^2+2(3)^2+3(5)^2+4(8)^2+3(9)^2+2(15)^2}{15}}$

$rms=\sqrt{69.73}$

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c

Generally the most probable speed is 8m/s as it the most posses by particles being the average

4 0

3 years ago

You measure the pressure of the four tires of your car each to be 35.0 pounds per square inch (psi). You then roll your car forw

Oksi-84 [34.3K]

Answer:

Weight of car = 36034.88 lb.ft/s²

Explanation:

We are told the pressure of the four tires of your car is; P = 35.0 psi

Also, the surface area of contact is; A = 32 in²

Thus;

Weight of tires = Pressure × Area

W_tires = 35 × 32

Weight_tires = 1120lb.

To get the weight of the car, we will multiply the tire weight by acceleration due to gravity.

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Thus;

Weight of car = 1120 × 32.174

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5 0

4 years ago