To solve this problem we will apply the concepts related to electric potential and electric potential energy. By definition we know that the electric potential is determined under the function:
= Coulomb's constant
q = Charge
r = Radius
At the same time
The values of variables are the same, then if we replace in a single equation we have this expression,
If we replace the values, we have finally that the charge is,
Therefore the potential energy of the system is 
Answer:
When object is placed between the focus (F) and pole (P) of a concave mirror, magnified and erect image of the object is formed on the back of the mirror.
When object is placed between the centre of curvature and the principal focus of a concave mirror, magnified and inverted image is formed in front of the mirror.
Explanation:
Considering the volume of a rectangle, the volume of the tissue box is 3,239.1 cm³.
<h3>What is volume</h3>
Volume is a scalar-type metric quantity that is defined as the extension in three dimensions of a region of space. In other words, the volume corresponds to the space that the shape occupies.
<h3>Volume of a rectangle</h3>
To calculate the volume of a rectangle, it is necessary to multiply its 3 dimensions: length ×width×height. Volume is expressed in cubic units.
<h3>Volume of the tissue box</h3>
In this case, you know:
- Length: 11.8 cm
- Width: 12.2 cm
- Height: 22.5 cm
Replacing in the definition of volume of a rectangle:
Volume of the tissue box= length ×width×height
Volume of the tissue box= 11.8 cm× 12.2 cm× 22.5 cm
Solving:
<u><em>Volume of the tissue box= 3,239.1 cm³</em></u>
Finally, the volume of the tissue box is 3,239.1 cm³.
Learn more about volume:
brainly.com/question/13535768
brainly.com/question/21172800
#SPJ1
At the top of the mountain, when he tightens the cap onto the bottole, there is some water and some air inside the bottle. Then he brings the bottle down to the base of the mountain.
The pressure on the outside of the bottle is greater than it was when he put the cap on. If anything could get out of the bottlde, it would. But it can't . . . the cap is on too tight. So all the water and all the air has to stay inside, and anything that can get squished into a smaller space has to get squished into a smaller space.
The water is pretty much unsquishable.
Biut the air in there can be <em>COMPRESSED</em>. The air gets squished into a smaller space, and the bottle wrinkles in slightly.
Answer:
The work done on the object by the force in the 5.60 s interval is 40.93 J.
Explanation:
Given that,
Force 
Mass of object = 2.00 kg
Initial position 
Final position 
Time = 4.00 sec
We need to calculate the work done on the object by the force in the 5.60 s interval.
Using formula of work done
Put the value into the formula
Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.
