Answer:
Broglie wavelength: electron 1.22 10⁻¹⁰ m
, proton 2.87 10⁻¹² m
, hydrogen atom 7.74 10⁻¹² m
Explanation:
The equation given by Broglie relates the momentum of a particle with its wavelength.
p = h /λ
In addition, kinetic energy is related to the amount of movement
E = ½ m v²
p = mv
E = ½ p² / m
p = √2mE
If we clear the first equation and replace we have left
λ = h / p =
λ = h / √2mE
Let's reduce the values that give us SI units
1 ev = 1,602 10⁻¹⁹ J
E1 = 100 eV (1.6 10⁻¹⁹ J / 1eV) = 1.6 10⁻¹⁷ J
We look in tables for the mass of the particle and the Planck constant
h = 6,626 10-34 Js
me = 9.1 10-31 Kg
mp = 1.67 10-27 Kg
Now let's replace and calculate the wavelengths
a) Electron
λ1 = 6.6 10⁻³⁴ / √(2 9.1 10⁻³¹ 1.6 10⁻¹⁷) = 6.6 10⁻³⁴ / 5.39 10⁻²⁴
λ1 = 1.22 10⁻¹⁰ m
b) Proton
λ2 = 6.6 10-34 / √(2 1.67 10⁻²⁷ 1.6 10⁻¹⁷) = 6.6 10⁻³⁴ / 2.3 10⁻²²
λ2 = 2.87 10⁻¹² m
c) Bohr's first orbit
En = 13.606 / n2 [eV]
n = 1
E1 = 13.606 eV
E1 = 13,606 ev (1.6 10⁻¹⁹ / 1eV) = 21.77 10⁻¹⁹ J
λ3 = 6.6 10⁻³⁴ /√(2 1.67 10⁻²⁷ 21.77 10⁻¹⁹) = 6.6 10⁻³⁴ / 8.52 10⁻²³
λ3 = 0.774 10⁻¹¹ m = 7.74 10⁻¹² m
In a perfectly ELASTIC collision between two perfectly rigid objects <span>both the momentum and the kinetic energy of the system are conserved.hope it helps</span>
Answer:
D
Explanation:
it lasts longer, for example batteries. if one lasts longer it has a higher strongness. but here it would be with lates and since the vilot one lasted longer its higher.
Answers:
a) 122.5 m
b) 50 m
Explanation:
Here we are dealing with projectile motion, where we can use the following two equations that model the parabolic motion of the stone after being thrown from the window:
(1)
(2)
Where:
is the height of the stone when it hits the ground
is the initial height of the stone
is the initial velocity of the stone
since we are told the stone was thrown horizontally
is the time the stone is in air
is the horizontal distance the stone travelled
Knowing this, we can answer the questions:
a)Initial height of the stone:
In this case we will isolate from (1):
(3)
(4)
(5) This is the initial height
b) Horizontal distance:
In this case we will use equation (2):
(6)
(7) This is the horizontal distance
Answer:
the decrease in energy is due to a transformational in internal energy of the body in the rebound.
Explanation:
For this exercise we can calculate the initial and final mechanical energy
Em₀ = U = m g y₁
= U = m g y₂
we look for the variation of the energy
ΔEm = Em_{f} - Em₀
ΔEm = m g (y_{f} -y₀)
ΔEm = m g (0.86 -1.2)
ΔEm = -3.332 m
We can see that there is a decrease in mechanical energy, this is transformed into internal energy of the ball during the impact with the ground, this energy can be formed by several factors such as a part of the friction with the surface, an increase in body temperature or a deformation of the body; there may be a contribution from several of these factors.
In conclusion the decrease in energy is due to a transformational in internal energy of the body in the rebound.