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TiliK225 [7]
3 years ago
14

Determine the weight of a 1350 kg rock as it falls off a cliff.

Physics
1 answer:
mr Goodwill [35]3 years ago
5 0

Answer:

13,230 N

Explanation:

F = mg

F = (1350 kg)(9.8 m/s²)

F = 13,230 N

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What amount of force is needed to propel and object of 27 kg to an acceleration of 11,550 m/s^2? (1 point)
aliya0001 [1]

Answer:

311,850 N

Explanation:

We can solve the problem by using Newton's second law:

F=ma

where

F is the net force applied on an object

m is the mass of the object

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For the object in this problem,

m = 27 kg

a=11550 m/s^2

Substituting, we find the force required:

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3 0
3 years ago
You're carrying a 3.0-m-long, 24 kg pole to a construction site when you decide to stop for a rest. You place one end of the pol
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Answer:

F=133N

Explanation:

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8 0
3 years ago
Question 2: In 2-4 sentences, explain what would happen to the cell if the nucleus didn’t work?
VladimirAG [237]

Answer:

Then the cell won't be able to function properly. With no nucleus the cell will lose control. It won't know what to do and there will be no cell division.

Explanation:

7 0
3 years ago
A cat dozes on a stationary merry-go-round, at a radius of 5.7 m from the center of the ride. Then the operator turns on the rid
tatyana61 [14]

Answer:

0.76

Explanation:

we are given:

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coefficient of friction (Uk) = ?

 we can get the minimum coefficient of friction from the equation below

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m x r x ω^{2} = Uk x m x g

r x ω^{2} = Uk x g

Uk = \frac{ r x ω^{2} }{g}

where ω (angular velocity) = \frac{2π}{time}

= \frac{2π }{5.5} = 1.14

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4 years ago
In free fall the object with less air resistance falls with a greater acceleration
ANEK [815]

terminal velocity ... greater speed ... acc is 10m/s/s

5 0
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