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3 years ago

5

Geometry peculiar pool

1 answer:

saw5 [17]3 years ago

5 0

Answer:

hi.

Step-by-step explanation:

download photo math

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Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur

Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel at the speed of light. You know that light can travel a distance of 5.88 x 10^12 miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

$9.3*10^7\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

so

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years$

This time is very small in years

Convert to minutes

$1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min$

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

$2.5*10^{13}\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

so

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years$

$4.25\ years< 5\ years$

therefore

The spaceship will get to Alpha Centaur in time

3 0

3 years ago

I am so lost, please help

skelet666 [1.2K]

Answer:

$u=\frac{9}{t}-\frac{1}{2} a t$

Step-by-step explanation:

Step 1: Given equation: $9=\frac{1}{2} a t^{2}+u t$

To get u, by subtraction equality property subtract both sides of the equation by $\frac{1}{2} a t^{2}$ .

$\Rightarrow 9-\frac{1}{2} a t^{2}=\frac{1}{2} a t^{2}+u t-\frac{1}{2} a t^{2}$

$\Rightarrow 9-\frac{1}{2} a t^{2}=u t$

Step 2: By division equality property, divide both sides of the equation by t.

$\Rightarrow \frac{9-\frac{1}{2} a t^{2}}{t}=\frac{u t}{t}$

$\Rightarrow \frac{9}{t}-\frac{1}{2} a t=u$

Therefore, $u=\frac{9}{t}-\frac{1}{2} a t$ .

So, in Emily’s physics class, she got $u=\frac{9}{t}-\frac{1}{2} a t$ .

7 0

3 years ago

A group of friends were working on a student film that had a budget of $700. They used 42% of their budget on equipment. How muc

goldfiish [28.3K]

Answer:

294

Step-by-step explanation:

100%-> 700

42%->294

5 0

3 years ago

Which system of equations is represented by the graph? Picture attached

STatiana [176]

None

the slope of the suggested lines is either 1 or -1
and none of the equal to the slope of the red line in the graph wichc is 2

6 0

4 years ago

Read 2 more answers

Micheal has 5^(2) boxes. There are 5^1 of apples in each box. When empty, a box weighs 5^-2 kg. What is the total weight of boxe

Bond [772]

Answer:

5.4

Step-by-step explanation:

Juss took the test

7 0

3 years ago