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3 years ago

Geometry peculiar pool

Mathematics

1 answer:

saw5 [17]3 years ago

5 0

Answer:

hi.

Step-by-step explanation:

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Find the GCF. 18c3 and 24c3

12345 [234]

Answer:

6c³

Step-by-step explanation:

18c³ = 2 × 3 × 3 × c × c × c

24c³ = 2 × 2 × 2 × 3 × c × c × c

Now we show the common factors in bold:

18c³ = 2 × 3 × 3 × c × c × c

24c³ = 2 × 2 × 2 × 3 × c × c × c

The common factor are:

2, 3, c, c, c

GCF = 2 × 3 × c × c × c = 6c³

6 0

3 years ago

Which is the better buy a 3 pound ham for $5.70 or 5 pounds for $8.75

tekilochka [14]

Answer:

The larger ham is the better buy.

Step-by-step explanation:

In order to determine the better buy, divide both of the prices by their weight to get the price per pound of ham.

5.70/3 = 1.90 per lb

8.75/5 = 1.75 per lb

Therefore the 5 pound of ham is a better buy.

7 0

3 years ago

Read 2 more answers

Find all the real cube roots of 1000/27 10/3 10/9 -10/9 -10/3

gulaghasi [49]

Can you do prime factoriztion

1000
100 * 10
10 * 10 * 10

27
9 * 3
3 * 3 * 3

cube root (1000/27) = 10/3

7 0

3 years ago

Read 2 more answers

In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en

jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

Step(i):-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in Swahili language

n(S) = 125

The probability that the fluent in Swahili language

$P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333$

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in English language

$P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9$

n(E∩S) = 95

The probability that the fluent in English and Swahili

$P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633$

Step(ii):-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

= 0.833+0.9-0.633

= 1.1

Final answer:-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0

3 years ago

Line L passes through the points (0, --3) and (6,9). (a) Find the equation of line L.

valentina_108 [34]

Step-by-step explanation:

Given points are :

$(0,\:-3)=(x_1,\:y_1) \:\&\: (6,\:9)=(x_2 ,\:y_2)$

Equation of line in two point form is given as:

$\frac{y -y_1 }{y_1 -y_2 } = \frac{x -x_1 }{x_1 -x_2 } \\ \\ \therefore \frac{y -( - 3)}{ -3 -9 } = \frac{x -0 }{0 -6 } \\ \\ \therefore \frac{y + 3}{ -12} = \frac{x }{ -6 } \\ \\ \therefore \frac{y + 3}{ 2} = \frac{x }{1} \\ \\ \therefore \: y + 3 = 2x \\ \\ \huge \red{ \boxed{\therefore \: 2x - y - 3 = 0}} \\ is \: the \: required \: equation \: of \: line.$

5 0

3 years ago