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3 years ago

In answering the following questions, assume that the angular acceleration is constant and nonzero: ??0.

Physics

1 answer:

saveliy_v [14]3 years ago

7 0

Answer:

Second equation

Explanation:

Solution:-

- Assuming that the initial and final rotational speed of the turn-table are known and the turntable have the a non zero constant angular acceleration (α):

α = (wf - wi) / t

t = (wf - wi) / α

- From the equation above we can directly find the time taken by the turntable to achieve the desired rotational speed. Where,

wi : initial rotational speed

wf : final/desired rotational speed

- The formula can be re-arranged to get:

wf = wi + α*t ...... (second equation in the list given)

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uppose one gallon of gasoline produces 1.17×108 J of energy, and this energy is sufficient to operate a car for 18.3 miles. An a

EleoNora [17]

Answer:

4.5 x 10^6 miles

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4 years ago

The triceps muscle in the back of the upper arm is primarily used to extend the forearm. Suppose this muscle in a professional b

taurus [48]

Answer:

I = 0.483 kgm^2

Explanation:

To know what is the moment of inertia I of the boxer's forearm you use the following formula:

$\tau=I\alpha$ (1)

τ: torque exerted by the forearm

I: moment of inertia

α: angular acceleration = 125 rad/s^2

You calculate the torque by using the information about the force (1.95*10^3 N) and the lever arm (3.1 cm = 0.031m)

$\tau=Fr=(1.95*10^3N)(0.031m)=60.45J$

Next, you replace this value of τ in the equation (1) and solve for I:

$I=\frac{\tau}{\alpha}=\frac{60.45Kgm^2/s ^2}{125rad/s^2}=0.483 kgm^2$

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8 0

3 years ago

A ball is thro.d hit the grouvelocity)?

kati45 [8]

Answer:

The velocity of the ball is 3.52 m/s.

Explanation:

A projectile is any object that moves under the influence of gravity and momentum only. Examples are; a thrown ball, a fired bullet, a kicked ball, thrown javelin, etc.

Given that the ball was thrown vertically upward on the top of a skyscraper of height 61.9 m. So that the velocity can be determined by;

u = $\sqrt{\frac{2H}{g} }$

Where: u is the velocity of the object, H is the height and g is the gravitational force on the object. Given that: H = 61.9 m and g = 10 m/ $s^{2}$ , then;