Answer:
The charge on the ball bearing 4.507 × 10^-8 C
Explanation:
From Coulomb's law
F = kq1q2/r²
make q2 the subject
q2 = Fr²/kq1
q2 = (1.8×10^-2 × 0.026²) ÷ (9×10^9 × 30×10^-9)
q2 = 4.507 × 10^-8 C
Answer:
I think the correct answer is the skier at the top.
Explanation:
cause potential energy is equal to mgh.
here mass and gravitational acceleration is same for all 3, but the top fellow has more height
Answer:
-8 Kgm/s
Explanation:
From conservation of linear momentum, the sum of momentum before collision is equal to the sum of linear momentum after collision
The sum of momentum before collision is 15+-35=-20 Kgm/s
Momentum after collision is
x+-12=-20
x=-20+12=-8 Kgm/s
20 rev =5 sec
1sec=4rev
1rev=1/4 sec
Time period =1/4
Frequency =4
<span>Occulation occurs when an object in outer space reaches the solar system and passes between earth and a far distant star, temporarily blocking light from the star. Occulation is an astronomy term referring to when an object in the foreground blocks the view of an object in the background.</span>