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iren2701 [21]
3 years ago
13

Please help with this problem.

Physics
1 answer:
pochemuha3 years ago
6 0

Answer:

its Y because the dot that represents it is close to S

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The resultant of two forces acting on the same point simultaneously will be the greatest when the angle between them is:a) 180 d
r-ruslan [8.4K]

Answer:

0 degrees

Explanation:

Let F_1\ and\ F_2 are two forces. The resultant of two forces acting on the same point is given by :

F_R=\sqrt{F_1^2+F_2^2+2F_1F_2\ cos\theta}

Where \theta is the angle between two forces

When \theta=0 i.e. when two forces are parallel to each other,

F_R=\sqrt{F_1^2+F_2^2+2F_1F_2\ cos(0)}

F_R=\sqrt{F_1^2+F_2^2+2F_1F_2}

When \theta=90^{\circ} i.e. when two forces are parallel to each other,

F_R=\sqrt{F_1^2+F_2^2+F_1F_2\ cos(90)}

F_R=\sqrt{F_1^2+F_2^2}

When \theta=180^{\circ} i.e. when two forces are parallel to each other,

F_R=\sqrt{F_1^2+F_2^2+F_1F_2\ cos(180)}

F_R=\sqrt{F_1^2+F_2^2-2F_1F_2}

It is clear that the resultant of two forces acting on the same point simultaneously will be the greatest when the angle between them is 0 degrees. Hence, this is the required solution.

8 0
3 years ago
Researchers condition a flatworm to contract when exposed to light by repeatedly pairing the light with electric shock. the elec
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Negative Reinforcement
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For a bronze alloy, the stress at which plastic deformation begins is 294 MPa and the modulus of elasticity is 121 GPa. (a) What
FromTheMoon [43]

Answer:

a) load in Newton is 96,138 b) 129.314mm

Explanation:

Stress = force/ area (cross sectional area of the bronze)

Force(load) = 294*10^6*327*10^-6 = 96138N

b) modulus e = stress/ strain

Strain = stress/ e = (294*10^6)/ (121*10^ 9) = 2.34* 10^ -3

Strain = change in length/ original length = DL/ 129

Change in length DL = 129 * 2.34*10^ -3 = 0.31347

Maximum length = change in length + original length = 129.314mm

7 0
2 years ago
An element becomes a positively charged ion when it
Anuta_ua [19.1K]
An element becomes a + ion when it...loses electrons
6 0
3 years ago
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At what minimum speed must a roller coaster be traveling when upside down at the top of a circle so that the passengers do not f
worty [1.4K]

Answer:

v_{min} \approx 17.153\,\frac{m}{s}

Explanation:

The roller coaster begins with maximum kinetic energy and no gravitational potential energy. The gravitational potential energy reaches its maximum when roller coaster is upside down at the top of the circle. The physical model for the roller coaster is constructed by means of the Principle of Energy Conservation:

\frac{1}{2}\cdot m \cdot v_{min}^{2} = m\cdot g \cdot h

The minimum velocity is:

v_{min} = \sqrt{2\cdot g \cdot h}

Let assume that radio of curvature is measured in meters. Hence:

v_{min} = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot(15\,m)}

v_{min} \approx 17.153\,\frac{m}{s}

8 0
2 years ago
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