Question

A supersonic airplane is flying horizontally at a speed of 2570 km/h. What is the centripetal acceleration of the airplane, if it turns from North to East on a circular path with a radius of 80.5 km? Submit Answer Tries 0/12 How much time does the turn take? Submit Answer Tries 0/12 How much distance does the airplane cover during the turn?

Answer 1

Answer:

6.33089870409 m/s²

708.5086 s

505796.417228 m

Explanation:

v = Velocity of the plane = $\dfrac{2570}{3.6}\ m/s$

r = Radius of turn = 80.5 km = 80500 m

Centripetal acceleration is given by

$a_c=\dfrac{v^2}{r}\\\Rightarrow a_c=\dfrac{(\dfrac{2570}{3.6})^2}{80500}\\\Rightarrow a_c=6.33089870409\ m/s^2$

Centripetal acceleration is 6.33089870409 m/s²

Time taken is given by

$t=\dfrac{2\pi r}{v}\\\Rightarrow t=\dfrac{2\pi\times 80500}{\dfrac{2570}{3.6}}\\\Rightarrow t=708.5086\ s$

The time taken is 708.5086 s

Distance covered will be the circumference

$d=2\pi\times 80500=505796.417228\ m$

The distance covered is 505796.417228 m