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11Alexandr11 [23.1K]
3 years ago
12

A supersonic airplane is flying horizontally at a speed of 2570 km/h. What is the centripetal acceleration of the airplane, if i

t turns from North to East on a circular path with a radius of 80.5 km? Submit Answer Tries 0/12 How much time does the turn take? Submit Answer Tries 0/12 How much distance does the airplane cover during the turn?
Physics
1 answer:
prisoha [69]3 years ago
8 0

Answer:

6.33089870409 m/s²

708.5086 s

505796.417228 m

Explanation:

v = Velocity of the plane = \dfrac{2570}{3.6}\ m/s

r = Radius of turn = 80.5 km = 80500 m

Centripetal acceleration is given by

a_c=\dfrac{v^2}{r}\\\Rightarrow a_c=\dfrac{(\dfrac{2570}{3.6})^2}{80500}\\\Rightarrow a_c=6.33089870409\ m/s^2

Centripetal acceleration is 6.33089870409 m/s²

Time taken is given by

t=\dfrac{2\pi r}{v}\\\Rightarrow t=\dfrac{2\pi\times 80500}{\dfrac{2570}{3.6}}\\\Rightarrow t=708.5086\ s

The time taken is 708.5086 s

Distance covered will be the circumference

d=2\pi\times 80500=505796.417228\ m

The distance covered is 505796.417228 m

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What must the charge (sign and magnitude) of a particle of mass 1.41 gg be for it to remain stationary when placed in a downward
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Answer:

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4 years ago
What does the process skill measuring mean?
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4 years ago
Read 2 more answers
35. An object of mass m moving at speed v0 strikes an object of mass 2m which had been at rest. The first object bounces backwar
MAVERICK [17]

Answer:

The collision is not elastic. The system increases his kinetic energy m*v₀² times.

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Assuming no external forces acting during the collision, total momentum must be conserved.

Considering the information provided, we can write the momentum conservation equation as follows:

m*v₀ = -m*v₀ + 2*m*vf

Solving for vf, we arrive to this somehow surprising result:

vf = v₀ (in the same direction that m was moving before the collision).

In order to determine if the collision was elastic, or not, we need to calculate the kinetic energy of the system before and after the collision:

K₀ = 1/2*m*v₀²

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As there is a net difference between the final and initial kinetic energies, and the total kinetic energy must be conserved in an elastic collision (by definition) we conclude that the collision is not elastic, and the change in the kinetic energy of the system is equal to m*v₀².

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A man can row at 6kmhr in still water and want to cross a river to a position exactly opposite his starting point. If the river
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Answer:

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