Answer:
x.get(0).
Explanation:
Arraylist provides dynamic arrays in Java means arrays that can resize themselves if needed.
We have arraylist x.We want to return the first element which will be stored at the index 0 because the indexing starts from 0.So 0 is the first index.
get(int index):- It return the element from the list at the specified index.
So we conclude the answer to this question is x.get(0).
Answer:
in the code snippet below, c. When System.out.println(a2) is executing, the toString() method is called.
d. When System.out.println(a1) is executing, the toString() method in class A gets called.
Explanation:
public class Test{
public static void main(String[] args){
Object a1 = new A();
Object a2 = new Object();
System.out.println(a1);
System.out.println(a2);
}
}
class A{
int x;
@Override
public String toString(){
return "A's x is " + x;
}
}
This is port 80 for clear-text connections and 443 for encrypted (TLS) connections.
Answer:
FamilyVacation FamilyVacation::operator+(int moreDays) {
FamilyVacation copy = *this;
copy.numDays += moreDays;
return copy;
}
Explanation:
You create a copy (which is simple because the class contains no pointers), then you modify the copy and return it.
Answer:
B. 192.168.258.4
Explanation:
The network layer in the OSI network model introduces the IP header to the data for transmission. This IP header contains the source and destination IP addresses.
IP address is a logical address given to network devices to allow routing of data to different points in a network. There are two versions of IP addresses and they are version 4 and 6.
The IP version 4 is a 32 bit address, divided into dot notations of four octet ( eight bits). Each 8 bits is equivalent to 256 possible address spaces, that is, 2^8 is equal to 256. The address space can not exceed 256.
Example of invalid IP address is 192.168.258.4, where the third octet exceeds 256.