1) Balanced chemical equation
H2SO4 + 2NaOH ---> Na2 SO4 + 2H2O
=> 1 mol H2SO4 : 2 moles NaOH
2) Convert 89.3 g of H2SO4 and 96.0 g of NaOH to moles
Molar mass of H2SO4 = 98.1 g/mol
Molar mass of NaOH = 40.0 g/mol
moles = mass in grams / molar mass
moles H2SO4 = 89.3 g / 98.1 g/mol = 0.910 mol
moles NaOH = 96.0 g / 40.0 g/mol = 2.40 mol
3) Theoretical molar ratio = 2 moles NaOH / 1 mol H2SO4
So, all the 0.91 mol of H2SO4 will be consumed along with 1.820 (2*0.91) moles of NaOH, and 0.580 moles (2.40 - 1.82) of NaOH will be left over by the chemical reaction.
4) Convert 0.580 moles NaOH to mass
0.580 moles * 40.0 g/mol = 23.2 g of NaOH will be left over
Answer:
Yes it is
Explanation: because it is composed of identical molecules consisting of atoms of two or more chemical elements.
hope it helps <3
1. Oil
2. Petroleum
Hope this helps
D. Same energy level but different sublevel.
<h3>Explanation</h3>
There are four quantum numbers [1]:
- <em>n</em><em>, </em>the principal quantum number,
- <em>l</em>, the orbital angular momentum quantum number,
- <em>
</em>, the magnetic quantum number, and - <em>
</em>, the electron spin quantum number.
As their names might suggest:
- <em>n </em>determines the main energy level of an electron.
- <em>l</em> determines the type of sublevel of an electron.
- Each sublevel might contain more than one orbital. <em></em> gives the orbital of an electron.
- Each orbital contains up to two electrons. <em></em> tells two electrons in the same orbital apart.<em> </em>
The two electrons in question come from the same atom. The question suggests that they have the same <em>n</em>, <em></em>, and <em></em>. As a result, both electrons are in main energy level <em>n</em> = 3. They share the same spin.
However, the two electrons differ in their value of <em>l</em>.
- <em>l </em>= 2 for the first electron. It belongs to a <em>d</em> sublevel.
- <em>l </em>= 1 for the second electron. It belongs to a <em>p</em> sublevel.
<h3>Reference</h3>
[1] Kamenko, Anastasiya, et. al, "Quantum Numbers", Physical & Theoretical Chemistry, Chemistry Libretexts, 24 Mar 2017.
The correct answer is base
