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erastovalidia [21]
3 years ago
9

A 280 mL bubble contains 0.283 g of a gas at 0.951 atm and 25.0°C What is the molar mass of this gas?

Chemistry
1 answer:
tekilochka [14]3 years ago
7 0

Answer: 28.3 g/mol

Explanation:

According to the ideal gas equation:'

PV=nRT

P= Pressure of the gas = 0.951 atm

V= Volume of the gas = 280 mL = 0.28 L     (1L=1000 ml)

T= Temperature of the gas = 25°C=(25+273)K=298 K   (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm/K mol

n=\frac{PV}{RT}=\frac{0.951\times 0.28L}{0.0821 \times 298}=0.010moles

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

0.010=\frac{0.283}{\text {Molar mass}}

{\text {Molar mass}}=28.3g/mol

Thus the molar mass of the gas is 28.3 g/mol.

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