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Oxana [17]
2 years ago
6

Given the reaction below, if 0.00345 g of carbon dioxide is used up, how many grams of water will be produced?

Chemistry
1 answer:
zimovet [89]2 years ago
3 0

From the  stoichiometry of the reaction, 1.4 * 10^-3 g is produced.

<h3>What mass of water is produced?</h3>

The equation of the reaction is written as; CO2 + 2LiOH → Li2CO3 + H2O. This can help us to apply the principle of stoichiometry here.

Thus;

Number of moles of CO2 = 0.00345 g/44 g/mol = 7.8 * 10^-5 moles

If 1 mole of CO2 produced 1 mole of water

7.8 * 10^-5 moles of CO2 produced  7.8 * 10^-5 moles of water

Mass of water produced =  7.8 * 10^-5 moles * 18 g/mol = 1.4 * 10^-3 g

Learn ore about stoichiometry:brainly.com/question/9743981

#SPJ1

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3 0
2 years ago
A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
natali 33 [55]

Answer:

There are 0.93 g of glucose in 100 mL of the final solution

Explanation:

In the first solution, the concentration of glucose (in g/L) is:

15.5 g / 0.100 L = 155 g/L

Then a 30.0 mL sample of this solution was taken and diluted to 0.500 L.

  • 30.0 mL equals 0.030 L (Because 30.0 mL ÷ 1000 = 0.030 L)

The concentration of the second solution is:

155 \frac{g}{L} *\frac{0.030L}{0.500L}=9.3\frac{g}{L}

So in 1 L of the second solution there are 9.3 g of glucose, in 100 mL (or 0.1 L) there would be:

1 L --------- 9.3 g

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8 0
4 years ago
What word chemical equation describes Cavendish’s experiment with zinc?
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This is an example of a single replacement reaction where zinc replaces hydrogen in the acid molecule.
3 0
3 years ago
Read 2 more answers
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