Question

Given the reaction below, if 0.00345 g of carbon dioxide is used up, how many grams of water will be produced?

Answer 1

From the  stoichiometry of the reaction, 1.4 * 10^-3 g is produced.

What mass of water is produced?

The equation of the reaction is written as; CO2 + 2LiOH → Li2CO3 + H2O. This can help us to apply the principle of stoichiometry here.

Thus;

Number of moles of CO2 = 0.00345 g/44 g/mol = 7.8 * 10^-5 moles

If 1 mole of CO2 produced 1 mole of water

7.8 * 10^-5 moles of CO2 produced  7.8 * 10^-5 moles of water

Mass of water produced =  7.8 * 10^-5 moles * 18 g/mol = 1.4 * 10^-3 g

Learn ore about stoichiometry:brainly.com/question/9743981

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