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stepladder [879]

3 years ago

15

Refer to the reaction between magnesium and oxygen In the introduction. What elements is oxidizing?write the oxidation number fo

r the reactants and product to show the oxidation

1 answer:

erica [24]3 years ago

7 0

Answer:

Oxidizing element: Mg

Explanation:

Reaction of magnesium and oxygen can be written as:

$2Mg +O_2 \rightarrow 2MgO$

while writting chemical reaction between two atom or element then write their natural form i.e. how that atom or element exist in the nature.

eg. reaction of any element with Oxygen atom then we can not write directly O because oxygen exist in the nature in form of $O_2$

finding oxidation number each side:

Reactant side:

Mg=0;

O=0;

product side:

Mg=+2;

O=-2;

from above:

oxidation number of Mg is increasing hence this is oxidizing element

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Determine the change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizi

uysha [10]

Answer: The change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizing compound is dissolved in it is $2.9^0C$

Explanation:

Elevation in boiling point:

$T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of pure carbon disulfide= $46.2^oC$

$k_b$ = boiling point constant = $2.34^0Ckg/mol$

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

$w_2$ = mass of solute = 35.0 g

$w_1$ = mass of solvent (carbon disulphide) = 397.7 g

$M_2$ = molar mass of solute = 70.0 g/mol

Now put all the given values in the above formula, we get:

$(T_b-46.2)^oC=1\times (2.34^oC/m)\times \frac{(35.0g)\times 1000}{70.0\times (397.7g)}$

$T_b=49.1^0C$

Therefore, the change in boiling point is $(49.1-46.2)^oC=2.9^0C$

5 0

3 years ago

If your creating a machine that will clean up trash from the ocean is that adding or removing thermal energy?

bogdanovich [222]

Answer: adding

Explanation:

Because it takes thermal energy to power it

6 0

3 years ago

Geologic time is a way to _______.

mylen [45]

Answer: Geologic time is a way to measure the sequence of events on Earth over time

Explanation:

3 0

3 years ago

The reaction below has an equilibrium constant kp=2.2×106 at 298 k. 2cof2(g)⇌co2(g)+cf4(g) calculate kp for the reaction below.

AnnZ [28]

<span>I believe the correct 2nd reaction is:</span>

cof2(g)⇌1/2 co2(g)+1/2 cf4(g)

where we can see that it is exactly one-half of the original

Therefore the new Kp is:

new Kp = (old Kp)^(1/2)

new Kp = (2.2 x 10^6)^(1/2)

<span>new Kp = 1,483.24 </span>

8 0

4 years ago

Read 2 more answers

A sample of 1.000 g of a compound containing carbon and hydrogen reacts with oxygen at elevated temperature to yield 0.692 g H₂O

ollegr [7]

Answer :

(a) 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) There is no other element present in the compound.

Explanation :

(a) Now we have to determine the masses of C and H in the sample.

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

where, 'x' and 'y' are the subscripts of Carbon and hydrogen respectively.

We are given:

Mass of $CO_2=3.381g$

Mass of $H_2O=0.692g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.381 g of carbon dioxide, $\frac{12}{44}\times 3.381=0.922g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.692 g of water, $\frac{2}{18}\times 0.692=0.0769g$ of hydrogen will be contained.

Thus, 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) Now we have to determine the compound contain any other elements or not.

Mass carbon + Mass of hydrogen = 0.922 g + 0.0769 g = 0.999 g ≈ 1 g

This means that there is no other element present in the compound.

3 0

3 years ago