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tankabanditka [31]
3 years ago
15

PLEASE ANSWER ASAP!!

Chemistry
1 answer:
Advocard [28]3 years ago
5 0

Answer:

the picture above should help you

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What is the correct answer ??
Ber [7]

Answer:

[H_3 O^+] = 1.0 ×10^-13

Explanation:

If we multiply the left side we get, 1e - 13. We add 13 to the right side while subtracting the remaining value from the left side (H3O+) than combine like terms. As you will get pH = 13.00

7 0
4 years ago
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Como clasificarias la máquina de la siguiente ilustración? tijera​
Lina20 [59]

Answer:

<u><em></em></u>

  • <u><em>máquina simple: palanca</em></u>

Explanation:

En vista de que  la pregunta está realizada en español, la respuesta la doy en el mismo lenguage.

La<em> palanca</em> es una máquina simple que consiste en una barra rígida que puede girar alrededor the un punto the pivote.

La forma en que functiona una palanca es que se aplica la ferza en el extremo de la barra que está más alejado del pivote. Este extremo puede desplazarse una larga distancia o arco, con una fuerza pequeña, haciendo que los puntos que están al otro lado del pivote, a una menor distancia de este, se desplacen una distancia o arco menor pero con más fuerza que la aplicada.

6 0
4 years ago
How many times greater is one gallon than one quart
horrorfan [7]
4, because there are 4 quarts in 1 gallon. 

Another way to think about it is 1 gallon= $1 and 1 quart= 25 cents 
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Hope this helped..
8 0
3 years ago
the pressure in a sealed plastic container is 108 kPa at 41 degrees Celsius. What is the pressure when the temperature drops to
Katarina [22]

<u>Answer:</u> The new pressure will be 101.46 kPa.

<u>Explanation:</u>

To calculate the new pressure, we use the equation given by Gay-Lussac Law. This law states that pressure is directly proportional to the temperature of the gas at constant volume.

The equation given by this law is:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are initial pressure and temperature.

P_2\text{ and }T_2 are final pressure and temperature.

We are given:

By using conversion factor:   T(K)=T(^oC)+273

P_1=108kPa\\T_1=41^oC=314K\\P_2=?kPa\\T_2=22^oC=295K

Putting values in above equation, we get:

\frac{108kPa}{314K}=\frac{P_2}{295K}\\\\P_2=101.46kPa

Hence, the new pressure will be 101.46 kPa.

3 0
3 years ago
Example of physical property
alisha [4.7K]

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Color. I thinkkk.

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