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tankabanditka [31]
3 years ago
15

PLEASE ANSWER ASAP!!

Chemistry
1 answer:
Advocard [28]3 years ago
5 0

Answer:

the picture above should help you

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Why are metals alloyed?
Lady_Fox [76]
Because alloys have qualities that are preferable to pure metals, almost all metals are utilised as alloys—that is, mixes of several elements. Alloying is done for a variety of purposes, the most common of which are to increase strength, corrosion resistance, or cost savings.
5 0
2 years ago
Which is a characteristic of all ions?
Brut [27]

Answer:

I guess B They have a charge

7 0
3 years ago
1. How much 6.0 M HNO3 is needed to neutralize 39 mL of 2.0 M KOH?
quester [9]

Answer:

For 2. the answer is 15.0 mL

For other examples, you can solve by exact way as I have solved the 2nd example.

I have writen down all the balanced chemical reaction equation for examples 1, 3, 4, 5 for you. ( picture 2 )

Explanation:

Please see the step-by-step solution in the picture attached below.(picture 1)

Hope this answer can help you. Have a nice day!

6 0
3 years ago
What is the mass, in grams, of a 12.0cm³ sample of aluminum? The density of aluminum is 2.70g/cm³
Levart [38]

Answer:

The answer is

<h2>32.4 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of aluminum = 12 cm³

Density = 2.70 g/cm³

The mass of aluminum is

mass = 2.7 × 12

We have the final answer as

<h3>32.4 g</h3>

Hope this helps you

4 0
3 years ago
Use the following balanced reaction to solve:
Naily [24]

Answer:  60.7 g of PH_3 will be formed.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given volume}}{\text{Molar volume}}    

\text{Moles of} H_2=\frac{60L}{22.4L}=2.68moles

The balanced chemical reaction is

P_4(s)+6H_2(g)\rightarrow 4PH_3(g)

H_2 is the limiting reagent as it limits the formation of product and P_4 is the excess reagent.

According to stoichiometry :

6 moles of H_2 produce = 4 moles of PH_3

Thus 2.68 moles of H_2 will produce=\frac{4}{6}\times 2.68=1.79moles  of PH_3

Mass of PH_3=moles\times {\text {Molar mass}}=1.79moles\times 33.9g/mol=60.7g

Thus 60.7 g of PH_3 will be formed by reactiong 60 L of hydrogen gas with an excess of P_4

3 0
3 years ago
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