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Anna007 [38]
3 years ago
13

A student reports the density of an article to be 1.92 g/mL. The accepted value of density is 1.89 g/mL. Calculate the student's

percent error.
Chemistry
1 answer:
ipn [44]3 years ago
6 0

Answer:

1.59%.

Explanation:

The following data were obtained from the question:

Measured density = 1.92 g/mL

Accepted density = 1.89 g/mL

Percentage error =...?

The percentage error error of the student can be obtained as follow:

Percentage error = |Measured density – Accepted density |/Accepted density × 100

Percentage error = |1.92 – 1.89|/1.89 × 100

Percentage error = 0.03/1.89 × 100

Percentage error = 1.59%

Therefore, the student percentage error is 1.59%

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Explanation:

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