An astronaunt in a space capsule orbiting the earth experience weightlessness. why?

1 answer:

3 0

Many students believe that orbiting astronauts are weightless because they do notexperience a force of gravity. ... While this is partly true, it does not explain their sense of weightlessness. The force of gravity acting upon an astronaut on the spacestation is certainly less than on Earth's surface.

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Two tuning forks of frequency 480 hz and 484 hz are struck simultaneously. what is the beat frequency resulting from the two sou

umka21 [38]

Ans: Beat frequency = $f_b$ = 4Hz

Explanation:
The beat frequency is equal to the absolute value of the difference in frequency of the two waves. In other words, the number of beats per second is equal to the difference in frequency. It is due to the destructive and constructive interference. According to this interference, sound will be soft or loud.

Hence. the formula is:
Beat frequency = $f_b = |f_2 - f_1|$

Since,
 $f_1 = 480Hz$
$f_2 = 484Hz$

Therefore,
Beat frequency = $f_b = |484 - 480|$

=> Beat frequency = $f_b = 4Hz$
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erastovalidia [21]

The answer is electrons

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2 years ago

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Brilliant_brown [7]

HELLO!

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Kate gathered 3 of the same size made of different materials: glas, clear plastic, and aluminum painted black. She placed on the

Anestetic [448]

Answer:

To relate the type of box material to the warmth inside the box 

Explanation:

3 boxes are made with three different materials glass, plastic and Aluminium. Thermal conductivity is different for different materials. thermal conductors allow easy flow of heat through them and insulators allow minimal or no flow of heat through them.

Thus the amount by which an object gets heated up depends on the value of its conductivity. In this experiment, glass and plastic are insulators and aluminium is a conductor. Among glass and plastic, plastic is a better insulator.

Thus the heat contained in the boxes will be of the order Aluminium>glass>plastic.

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1. An express train, traveling at 36 m/s, is accidentally sidetracked onto a local train track. The express engineer spots a loc

Colt1911 [192]

Answer:

(i) 12 seconds

(ii) 216 meters from the initial position

(iii) 132 meters from the initial position

(iv) No

Explanation:

Speed of express train =36 m/s