Well what i got was 79.3 by finding the average by adding it all together then divided it by how many numbers
Answer:
The area of the shaded region is 42.50 cm².
Step-by-step explanation:
Consider the figure below.
The radius of the circle is, <em>r</em> = 5 cm.
The sides of the rectangle are:
<em>l</em> = 11 cm
<em>b</em> = 11 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Thus, the area of the shaded region is 42.50 cm².
Answer:
0.0668 = 6.68% probability that the worker earns more than $8.00
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The average hourly wage of workers at a fast food restaurant is $7.25/hr with a standard deviation of $0.50.
This means that 
If a worker at this fast food restaurant is selected at random, what is the probability that the worker earns more than $8.00?
This is 1 subtracted by the pvalue of Z when X = 8. So



has a pvalue of 0.9332
1 - 0.9332 = 0.0668
0.0668 = 6.68% probability that the worker earns more than $8.00
BANK A:
5,000*0.03*5=750
BANK B:
5,000*0.025*6=750
They are the same
Answer:
Step-by-step explanation:
When,x= -1
Now,
f(-1)=-(-1)^2+6
=1+6
=7
Hope it helped you.