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3 years ago

11

Many U.S employees received a 3% raise in 2012. Suppose an employee made $47,000 in 2011 and received a 3% raise. What did she m

ake in 2012? Show 2 different ways to answer the question.

1 answer:

Hoochie [10]3 years ago

7 0

First lets get 3% into decimal form.

3% is 3/100 = 0.03

Now multiply 0.03 by 47000 to get how much extra money she was going to get.

47000 * 0.03 = 1410

Now we just add
47000 + 1410 = 48410 is what she was going to make in 2012

Another way to do this is

(47000)(1+0.03) = 48410

you would use (1+0.03) which tells you she increased in pay.

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A researcher is interested in determining if the more than two thirds of students would support making the Tuesday before Thanks

klio [65]

Answer:

a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they are in favor of making the Tuesday before Thanksgiving a holiday, or they are against. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

So, the binomial probability distribution has two parameters, n and p.

In this problem, we have that $n = 1000$ and $p = \frac{700}{1000} = 0.7$ . So the parameter is

a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.

8 0

3 years ago

Standard deviation of 300, 785, 670, 187, 760, 724

White raven [17]

STEP 1

Mean = $\frac{300+785+670+187+760+724}{6} = \frac{3426}{6}=571$

STEP 2

Subtract the mean from each data value then square the answer
$300-571=-271$ ⇒ $(-271)^{2} =73441$
$785-571=214$ ⇒ $(214)^{2}=45796$
$670-571=99$ ⇒ $(99)^{2}=9801$
$187-571=-384$ ⇒ $(-384)^{2} =147456$
$760-571=189$ ⇒ $189^{2}=35721$
$724-571=153$ ⇒ $153^{2} =23409$

STEP 3

Add the squared answers in STEP 2 then find the mean

$\frac{73441+45796+9801+147456+35721+23409}{6}= \frac{335624}{6}=55937.3$

STEP 4

Square root the answer in STEP 3
$\sqrt{55937.3} =236.5$

Standard deviation is 236.5

7 0

3 years ago

For which product or quotient is this expression the simplest form? (image attached)! please help :((

mars1129 [50]

Answer:

D

Step-by-step explanation:

For simplify the work we can start to factorise all the possibles expressions:

2x + 8.

8 is multiple of 2, so it can became

2(x+4)

x^2 - 16 this is a difference of two squares, so it can be rewritten as:

(x+4)(x-4)

x^2 + 8x + 16

we have to find two numbers whose sum is 8 and whose product is 16

the two number are 4 and 4

it becames:

(x+4)(x+4)

x+ 4 can‘t be simplified

if we look at the expression, we can find that x-4 appears at the numerator so

x^2 - 16 must be at numerator

but the second factor (x+4) doesn’t appear, so has been simplified. This situation can be possible only in the D option

in fact

(x+4)(x-4)/2(x+4) * (x+4)/(x+4)(x+4)

it became

(x+4)(x-4)/2 * 1/(x+4)(x+4)

(x-4)/2(x+4)

4 0

3 years ago

John has gross biweekly earnings of $743.61. By claiming 1 more withholding allowance, John would have $19 more in his take home

Afina-wow [57]

Answer:

Total withholding allowances are 39.

Step-by-step explanation:

Given the gross earning of John = $743.61

It is given that 1 withholding allowance = $19

Now we have to find the total number of withholding allowances. Here, the number of withholding allowances can be determined by dividing the total earnings with $19.

Number of withholding allowances = 743.61 / 19 = 39.14 or 39 (round off).

4 0

3 years ago

Solve for x. <br> 5(x-10)=30-15x

almond37 [142]

5x-50= 30-15x

20x= 80

x= 4 is the solution to this problem

5 0

4 years ago