Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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1 pt; or 1 pint seems most reasonable here.
Answer:
12
7
2
- 3
- 8
Step-by-step explanation:
f ( - 2 )
= 2 - 5 ( - 2 )
= 2 - ( - 10 )
= 2 + 10
= 12
f ( - 1 )
= 2 - 5 ( - 1 )
= 2 - ( - 5 )
= 2 + 5
= 7
f ( 0 )
= 2 - 5 ( 0 )
= 2
f ( 1 )
= 2 - 5 ( 1 )
= 2 - 5
= - 5 + 2
= - 3
f ( 2 )
= 2 - 5 ( 2 )
= 2 - 10
= - 10 + 2
= - 8
Answer:
Zeros would be x= 0, -2
Step-by-step explanation:
hope this helps :)
