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Firdavs [7]
3 years ago
7

An isosceles triangle has two sides of equal length, a, and a base, b. The perimeter of the triangle is 15.7 inches, so the equa

tion to solve is 2a + b = 15.7. If we recall that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side, which lengths make sense for possible values of b? Select two options. –2 in.
Mathematics
1 answer:
Nat2105 [25]3 years ago
6 0

Answer:

Step-by-step explanation:

b  must not be an even number

2a>b

a+b>a

so b could be 3.1, 3.3, ......7.7

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krek1111 [17]

Answer:

a=-3

Step-by-step explanation:

we have

a-2=\frac{3+6a}{3}

Solve for a

That means ----> Isolate the variable a

Factor 3 in the numerator right side

a-2=\frac{3(1+2a)}{3}

Simplify right side

a-2=1+2a

subtract a both sides

a-2-a=1+2a-a

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subtract 1 both sides

-2-1=1+a-1

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Rewrite

a=-3

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3 years ago
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Answer:

\checkmark \text{B. The area of the circle is } 729\pi,\\\checkmark \text{D. The arc length of the sector is } 12\pi

Step-by-step explanation:

Area of a circle with radius r: r^2\pi

Circumference of a sector with radius r: 2r\pi

Area of sector with angle \theta:  r^2\pi\cdot \frac{\theta}{360}.

Arc length of sector with angle \theta: 2r\pi\cdot \frac{\theta}{360}

Using these equations, we get the following information:

Area of circle: 27^2\pi=729\pi

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Arc length of sector: 2\cdot 27\cdot \pi \cdot \frac{80}{360}=12\pi

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Answer:

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UV+VW=UW

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