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Vadim26 [7]
2 years ago
6

Which number has a greater value than |-2.6|?

Mathematics
2 answers:
Archy [21]2 years ago
4 0

Answer: I'm assuming that there were multiple choices provided for this question.. but just to help you, when a number is within the absolute value, it changes any number to a positive:

|-2.6| = 2.6

So any number higher than that work for this question :-)

ki77a [65]2 years ago
3 0
It’s 2.$ since it can never be negative
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Suppose that P(A) = 0.25 and P(B) = 0.40 . If P(A|B)=0.20 , what is P(B|A) ?
Ket [755]

Answer:

  • 0.32

Step-by-step explanation:

<u>Use of formula:</u>

  • P(A and B) = P(A)*P(B|A) and
  • P(A and B) = P(B)*P(A|B)

<u>According to above and based on given:</u>

  • P(A)P(B|A) = P(B)P(A|B)
  • P(B|A) = P(A|B)*P(B)/P(A)
  • P(B|A) = 0.20*0.40/0.25 = 0.32
8 0
2 years ago
Solve equation using square roots (x-1)^2=4
Aneli [31]
X is equal 3. to do this, you do reverse of order of operations. So this means that you would to the 'times 2' first by dividing 4 by 2 to make it 2. then, in the parenthesis, since there is a 'minus 1', therefore you are going to add 1+2 which equals three.  <span />
4 0
3 years ago
In rectangle ABCD, point E lies half way between sides AB and CD and halfway between sides AD and BC. If AB=3 and BC=2, what is
Alex777 [14]

Answer:

<em>The area of the shaded region is 3.</em>

Step-by-step explanation:

Since point E lies halfway between AB and BC, the area of the shaded region (As) consists of two identical triangles with base equal to AB and height equal to half the measure of BC:

A_s=2 * A_t

Where At is the area of each triangle.

\displaystyle A_t=\frac{AB*BC/2}{2}

\displaystyle A_t=\frac{AB*BC}{4}

We know AB=3 and BC=2, thus:

\displaystyle A_t=\frac{3*2}{4}=\frac{6}{4}

Simplifying:

\displaystyle A_t=\frac{3}{2}

Finally:

\displaystyle A_s=2 * \frac{3}{2}

A_s=3

The area of the shaded region is 3.

Note the area of the shaded region is half the area of the rectangle.

3 0
2 years ago
Please help
Varvara68 [4.7K]

Answer:

$6 = cost of small box

$8 = cost of large box

Step-by-step explanation:

Let s = cost of small box

     l  = cost of large box

(1)    12s + 3l = 96            (2)     6s + 6l = 84

    Multiply by -2                    <u> -24s - 6l = -192</u>

                                                -18s   = - 108

                                                     s = $6 = cost of small box

      12(6) + 3l = 96

         72 + 3l = 96

                 3l = 24

                   l = $8 = cost of large box

7 0
2 years ago
(1 pt)
LekaFEV [45]
B it is going to give you the answer
4 0
3 years ago
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