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4 years ago

Why do we use gold and silver to make jewellery?

Chemistry

1 answer:

Firdavs [7]4 years ago

3 0

Explanation:

Gold and Silver is used for making ornaments because of their malleability and durability. Gold is the most malleable metal. For e.g, a small piece is gold nearly 3.5gm can be made a kilometer thin wire. Gold and and silver are also very lusturous and looks very much lookrative.

Hope this helps

You might be interested in

When a substance evaporates, what happens to the mass? (4 points)

kirza4 [7]

Answer: C) The mass stays constant as it changed from a liquid to a gas

Explanation: Mass stays constant, it's never destroyed or created. It follows the law of conservation of mass.

5 0

4 years ago

An analytical chemist is titrating 242.5 mL of a 1.200 M solution of hydrazoic acid HN3 with a 0.3400 M solution of NaOH. The pK

rodikova [14]

Answer:

The pH of the solution is 12.61

Explanation:

Step 1: Data given

Molarity of hydrazoic acid solution = 1.200 M

Volume of solution = 242.5 mL

Molarity of NaOH solution = 0.3400 M

pKa = 4.72

Step 2: The balanced equation

HN3 + NaOH → NaN3 + H2O

Step 3: Calculate moles hydrazoic acid

Moles hydrazoic acid = molarity * volume

Moles hydra

zoic acid = 1.200 M * 0.2425 L

Moles hydrazoic acid = 0.291 moles

Step 4: Calculate moles NaOH

Moles NaOH = 0.3400 M * 1.006 L

Moles NaOH = 0.342 moles

Step 5: Calculate the limiting reactant

HN3 is the limiting reactant. It will completely be consumed (0.291 moles)

NaOH is in excess. There reacts 0.29 moles. There will remain 0.342 - 0.291 = 0.051 moles NaOH

Step 6: Calculate total volume

Total volume = 242.5 mL + 1006 mL = 1248.5 mL = 1.2485 L

Step 7: Calculate molarity of NaOH

Molarity NaOH = 0.051 moles / 1.2485 L

Molarity NaOH = 0.0408 M

Step 8: Calculate pOH

pOH = -log [OH-] = -log(0.0408)

pOH = 1.39

Step 9: Calculate pH

pH = 14 - pOH

pH = 14 - 1.39

pH = 12.61

The pH of the solution is 12.61

7 0

3 years ago

Need help on B and C please!!

puteri [66]

B. The reason the temperature experienced no change in group c is because it was likely the control group.
I cannot read question c, the monitor refresh is obscuring the text.

5 0

3 years ago

4 C3H6 + 6 NO --> 4 C3H3N + 6 H2O + N2

emmasim [6.3K]

4 moles

Explanation:

Given parameters:

number of moles of reacting NO = 24moles

Equation of the reaction:

4C₃H₆ + 6NO ⇒ 4C₃H₃N + H₂O + N₂

Solution:

The moles is synonymous the quantity of matter that contains the avogadro's number of particles.

To solve this problem, we must ensure that the given equation is balanced by simply inspecting.

The equation is balanced by inspection.

From the balanced equation;

6 moles of NO reacted to produce 1 mole of nitrogen gas

24 moles of NO will therefore produce $\frac{24}{6}$ = 4 moles

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

5 0

4 years ago

How many grams of Chromium(III) nitrate are produced when Chromium reacts with 0.85 moles of Lead(IV) nitrate to produce chromiu

mina [271]

Grams of Chromium(III) nitrate produced : 268.95 g

<h3>Further explanation</h3>

Given

0.85 moles of Lead(IV) nitrate

Required

grams of Chromium(III) nitrate

Solution

Reaction

Balanced equation :

2Cr₂ + 3Pb(NO₃)₄ ⇒ 4Cr(NO₃)₃ + 3Pb

From the equation, mol ratio of Pb(NO₃)₄ : Cr(NO₃)₃ = 3 : 4, so mol Cr(NO₃)₃

mol Cr(NO₃)₃ =

$\tt \dfrac{4}{3}\times 0.85=1.13$

Mass of Chromium(III) nitrate (MW=238.0108 g/mol) :

mass = mol x MW

mass = 1.13 x 238.0108

mass = 268.95 g

7 0

3 years ago