Explanation:
(a)
Cancelling common terms, the overall reaction is as follows:
(b)
Chemical species which are generated and consumed during the reaction are called intermediates. Therefore, in the given reaction, HClO(aq), OH-(aq) and HIO(aq) are intermediate species.
(c)
two reactant molecules are involved in each steps, therefore, each steps are bimolecular. Since water is in excess, therefore will not be rate law
Rate law for first step:
Rate law for second step:
Rate law for third step:
(d)
Step 2 is slow step, therefore this step will be rate determining step.
So, rate = k [I-] [HClO]
So, it consisted with the actual rate law
A. combustion
because carbon dioxide is the main product of burning carbon based fuels and combustion is the process of burning something
<span>1.006 g of Na2CO3 is left; which means that (2.714 -1.006) g of water are lost from the hydrated sodium carbonate
So, water present = </span>(2.714 -1.006) = 1.708 g.
Molecular Wt. of water is =18 g
so moles = 1.708/18 moles = 0.095 moles.
Now, <span>Na2CO3 has molecular wt. of = 23x2 + 12 +3x16 = 106 g,
so moles of Na2CO3 = 1.006/106 moles = 0.0095 moles </span>
<span>Ratio is = 0.0095 / 0.095 = 1 / 10 [ moles of Na2CO3 / moles of H2O ]
Ratio is saying on every 1 mole of Na2CO3 , there are 10 moles of H2O
so x is 10</span>