What is the mass of 3.2×10²³ molecules of CH4?

Inessa [10]

Film badges is a personal dosimeter used for monitoring cumulative radiation dose due to ionizing radiation.

A panel or layers of photographic film covered with black paper and exposed to air ,salt,and other chemicals on clear acetate

8 0

3 years ago

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What is the symbol for aluminum and sulphur ?

borishaifa [10]

<em><u>The formula for aluminum sulfide is Al2 S3.</u></em>

<h2><em>hope it helps</em><em>!</em></h2>

4 0

3 years ago

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If this compounds (N2O) molecular mass is 88g are the empirical and molecular formulas the same as one another or different

Softa [21]

Answer:

No

Explanation:

Let us examine this problem carefully:

Given compound is N₂O

Molecular mass = 88g

Now,

The empirical formula is the simplest formula of a compound.

The molecular formula is the true formula of the compound that shows that actual ratios of the atoms in a compound.

To find if they both have the same molecular and empirical formula, they must have the same molecular mass.

For N₂O;

Molecular mass = 2(14) + 16 = 44g/mole

But the true and given molecular formula of the compound is 88g/mole

This shows that the compound given is the empirical formula of the compound.

Molecular formula:

molecular mass of empirical formula x n = molecular mass of molecular formula

n = $\frac{88}{44}$ = 2

Molecular formula of compound = 2(N₂O) = N₄O₂

Therefore the empirical and molecular formulas are not the same

8 0

3 years ago

Which of the following statements is (are) incorrect?

Stells [14]

Answer:

1. A.

All statements are correct.

2.E

Explanation:

I. The hybridization of boron in BF3 is sp2

Hybridization is simply the mixing of orbitals to form new orbitals. In the above instance, one s orbital had mixed with 2 p orbitals.

Firstly, to get this hybridization, we draw the Lewis structure I.e using dots to represent the number of valence electrons on the atoms.

Boron has five valence electrons and hence it needs three more to complete an octet. This can be completed by sharing one electron from each of the fluorine atom.

Now, the hybridization is sp2 because a single pi bond is required for the double bond between the boron and only three sigma bonds are formed per boron atom.

II. The molecule XeF4 is non polar

It is non polar because it has no plane of symmetry.

III. The bond order of N2 is three.

Bond order is mathematically equal to = (number of electrons in the bonding orbital - number of electrons in the non bonding orbital)/2

The number of electrons in the bonding are 6 while the number of electrons in the nonbonding orbital is zero. Calculating this yields 6/2 = 3

IV. The molecule HCN has 2 pi bonds and 2 sigma bonds

2. Hybridization of I3- is sp3d

To know the number of hybrid bonds, we simply add the number of lone pairs with that of the neighbours and that's 3 + 2 = 5

Thus, the hybridization is sp3d

6 0

3 years ago

Write the rate law for the reaction of S2O8^2-

Tamiku [17]

the rate law should be k[S2O8^-2]

7 0

3 years ago