The range of a projectile is the maximum horizontal distance between the point of origin to the end point. It can be calculated through the equation,
range = v²sin2θ/g
where v is the initial velocity, θ is the angle, and g is the gravitational constant.
Substituting the known values,
range = (36 m/s)² x (sin2(28°)) / 9.8 m/s²
range = 109.64 m
Thus, the range of the golf ball is approximately 109.64 m.
Answer:
All the objects experience the same acceleration
Explanation:
According to Newton's law of universal gravitation, we have the gravitational force F given by the relation;
Where;
G = The universal gravitational constant
M₁ = The mass of the Earth
m₂ = The mass of the object in the Earths gravitational field
R = The radius of the Earth
Therefore, we have;
Which gives;
Therefore, based on the above calculation, all three object will have the same acceleration due to gravity, g, when air resistance is ignored.
Answer:
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Explanation:
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Answer:
The back end of the vessel will pass the pier at 4.83 m/s
Explanation:
This is purely a kinetics question (assuming we're ignoring drag and other forces) so the weight of the boat doesn't matter. We're given:
Δd = 315.5 m
vi = 2.10 m/s
a = 0.03 m/s^2
vf = ?
The kinetics equation that incorporates all these variables is:
vf^2 = vi^2 + 2aΔd
vf = √(2.1^2 + 2(0.03)(315.5))
vf = 4.83 m/s