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3 years ago

if Xc = 7,500 and the resistance is 10,000 in a series RC circuit , what is the impedance of the circuit?

Physics

2 answers:

mr_godi [17]3 years ago

3 0

Answer:

The impedance of the circuit = 12500 Ω

Explanation:

Impedance: This is the overall opposition to the flow of current in an a.c circuit by any two or all of the three circuit elements.(R, L, C) is called impedance.

The S.I unit of Impedance is Ohms. (Ω), It can be represented mathematically as

Z = √(Xc² + R²).................... Equation 1

Where Z = impedance, Xc = reactance of the capacitor, R = resistance of the resistor.

Given: Xc = 7500 Ω, R = 10000 Ω

Substituting these values into equation 1,

Z = √(7500² + 10000²)

Z = √(56250000 + 100000000)

Z = √(156250000)

Z =12500 Ω

Therefore, The impedance of the circuit = 12500 Ω

Bumek [7]3 years ago

3 0

Answer: Impedance Z = 12500 ohms

Explanation:

Given;

Capacitive resistance Xc = 7500 ohms

Resistance R = 10000 ohms

The general formula for impedance is;

Z = √(R^2 + (Xc + Xl)^2)

Where Xl is the inductive resistance

Z is impedance

For a RC circuit, impedance is

Z = √(R^2 + Xc^2).

Z = √(10000^2 + 7500^2)

Z = 12500 ohms

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A stone was dropped off a cliff and hit the ground with a speed of 88 ft/s. What is the height (in feet) of the cliff

igor_vitrenko [27]

Answer:

the height (in feet) of the cliff is 121 ft

Explanation:

A stone hit the cliff with

speed, v = 88 ft/s

Acceleration, a= 32 ft/s^2

initial speed, u = 0 ft/s

height is h.

To solve this problem we will apply the linear motion kinematic equations, Equation of motion describes change in velocity, depending on the acceleration and the distance traveled

so, writing the formula of Equation of motion:

v^2 - u^2 = 2*a*h

substituting the appropriate values,

(88)^2 - 0 = 2*32* h

h=(88)^2 / 64

h= 121 ft

hence

the height (in feet) of the cliff is 121 ft

learn more about height of the cliff here:

brainly.com/question/24130198

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2 years ago

Where must an object be placed to form an image 30.0 cm from a diverging lens with a focal length of 43.0 cm?

Schach [20]

Using lens equation;

1/o + 1/i = 1/f; where o = Object distance, i = image distance (normally negative), f = focal length (normally negative)

Substituting;

1/o + 1/-30 = 1/-43 => 1/o = -1/43 + 1/30 = 0.01 => o = 1/0.01 = 99.23 cm

Therefore, the object should be place 99.23 cm from the lens.

6 0

3 years ago

A golf ball has a mass of 120g. Calculate its increase in mass when it is travelling at 40ms1. What is this as a percentage of i

kicyunya [14]

Answer:

$Percentage=8.889\times 10^{-13}$ %

Explanation:

From special theory of relativity the dynamic mass m is related with the rest mass $m_{0}$ of the body as

$m=\frac{m_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }$

Here, c is the speed of light and v is the velocity of object.

Given mass of the golf ball is 120 g.

$m=\frac{120 }{\sqrt{1-\frac{(40)^{2} }{(3\times 10^{8} )^{2} } } }\\m=120(1-\frac{(40)^{2} }{(3\times 10^{8}) ^{2} })^{-\frac{1}{2} } \\$

Now applying the binomial theorem and solve the above equation.

$m=(1+\frac{1}{2}(\frac{40}{3\times 10^{8} }) ^{2} )\\m=120(1+8.889\times 10^{-15})$

Therefore, increase in mass is,

$\Delta m=120\times 8.889\times 10^{-15} \\\Delta m=10.6668\times 10^{-13} g$

Now percentage of increase in mass with rest mass is,

$Percentage=\frac{10.6668\times 10^{-13} g}{120g} \times 100\\Percentage=8.889\times 10^{-13}$

Therefore, the percentage of increase in mass with rest mass is $Percentage=8.889\times 10^{-13}$ .

4 0

4 years ago

A 2:2 kg toy train is con ned to roll along a straight, frictionless track parallel to the x-axis. The train starts at the origi

Liula [17]

Answer:

a) 10.51 J

b) 3.48 m/s

Explanation:

Given data :

mass of train ( M ) = 2.2 kg

Given initial velocity ( u ) = 1.6 m/s

a) calculating work done by the force over the journey of the train

F = mx + b ------ ( 1 )

m = slope = ( Δ f / Δ x ) = 2.8 / -7.5 = - 0.373 N/m

x = distance travelled on the x axis by the train = 7.5 m

F = force experienced by the train = 2.8 N

x = 0

∴ b = 2.8

hence equation 1 can be written as

F = ( -0.373) x + 2.8 ----- ( 2 )

hence to determine the work done by the force

W = $\int\limits^7_0 { ( -0.373) x + 2.8 )} \, dx$ Note: the limits are actually 7.5 and 0

∴ W ( work done ) = -10.49 + 21 = 10.51 J

b) calculate the speed of the train at the end of its journey

we will apply the work energy theorem

W = 1/2 m*v^2 - 1/2 m*u^2

∴ V^2 = 2 / M ( W + 1/2 M*u^2 ) ( input values into equation )

V^2 = 12.11

hence V = 3.48 m/s

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3 years ago

True or false Momentum, like velocity, is described by both a direction and a force

VARVARA [1.3K]

Yes, momentum, like velocity, has a direction, and is a vector. (even though it isn't mentioned very often in these high-school problems).

Its direction is the same as the direction of the velocity that it's made of.

But the statement is a bit sloppy . . . It's true that momentum has a direction just like velocity has. But neither of them involves "a force".

Velocity is a direction with a SPEED.

Momentum is a direction with a product of (mass) x (velocity).

8 0

3 years ago