Answer:
The impedance of the circuit = 12500 Ω
Explanation:
<em>Impedance:</em> This is the overall opposition to the flow of current in an a.c circuit by any two or all of the three circuit elements.(R, L, C) is called <em>impedance.</em>
<em>The S.I unit of Impedance is Ohms. (Ω), It can be represented mathematically as</em>
Z = √(Xc² + R²).................... Equation 1
Where Z = impedance, Xc = reactance of the capacitor, R = resistance of the resistor.
<em>Given: Xc = 7500 Ω, R = 10000 Ω</em>
<em>Substituting these values into equation 1,</em>
<em>Z = √(7500² + 10000²)</em>
<em>Z = √(56250000 + 100000000)</em>
<em>Z = √(156250000)</em>
Z =12500 Ω
Therefore, The impedance of the circuit = 12500 Ω