Answer:
0.108 rad/s².
Explanation:
Given that
Initial angular velocity ,ωi = 0 rad/s
Final angular velocity ωf= 0.5 rev/s
We know that
1 rev/s = 6.28 rad/s
ωf= 3.14 rad/s
t= 28.9 s
We know that (if acceleration is constant)
ωf=ωi + α t
α=Angular acceleration
3.14 = 0 + α x 28.9
Therefore the acceleration will be 0.108 rad/s².
Therefore the answer will be 0.108 rad/s².
Answer:
0.25A
1.0A
2.5A
Explanation:
this is only for the calculated current column on edge
Answer:
36.408cm3
Explanation:
Since we acknowledge that density is d= m/v, once we switch it up to maintain v as the number to be found it will change to v=m/d. Therefore, 275.32/7.562 is 36.408 and the unit is cm cube!
Hope that helped!!
Given that amplitude and energy are related, the amplitude of a wave is dependent upon A. the amount of energy carried by the wave.
These two are connected, so one affects the other and vice versa.
Answer: 
Energy is directly proportional to the frequency.
The energy of a photon is given by:

Where, E is the energy and
is the frequency.
Frequency of the radio wave is given:


Multiply the above two:
Energy,

Hence, the energy of each photon of radio wave having frequency
is 