Answer:
it's x that is the right answer
Answer:
The magnitude of the magnetic field B at the center of the loop is 5.0272 x 10⁻⁴ T.
Explanation:
Given;
Radius of circular loop, R = 3.00 cm = 0.03 m
Current in the loop, I = 12.0 A
Magnetic field at the center of circular loop is given as;
B = μ₀I / 2R
Where;
μ₀ is constant = 4π x 10⁻⁷ T.m/A
R is the radius of the circular loop
I is the current in the loop
Substitute the given values in the above equation and calculate the magnitude of the magnetic field;
B = (4π x 10⁻⁷ x 12)/ 0.03
B = 5.0272 x 10⁻⁴ T
Therefore, the magnitude of the magnetic field B at the center of the loop is 5.0272 x 10⁻⁴ T.
Answer:
7.48 x 10⁵ m
Explanation:
g = 7.86 N/kg
M = 5.97 x 10²⁴ kg, R = 6.37 x 10⁶ m.
Find height h
g = GM/(R + h)²
(R + h)² = GM/g = 6.67 x 10⁺¹¹ x 5.97 x 10²⁴ /7.86 = 5.066 x 10¹³
R + h = 7.12 x 10⁶ m
so
h = 7.12 x 10⁶ - 6.37 x 10⁶ = 7.48 x 10⁵ m
3 as a single number is considered a sf
