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Fittoniya [83]
3 years ago
6

Gretchen and Ezia received equal scores on a test made up of multiple choice questions and an essay. Gretchen got 18 multiple ch

oice questions correct and received 19 points for her essay. Ezia got 15 multiple choice questions correct and received 31 points for her essay.
How many points was each multiple choice question worth?
Enter your answer in the box.
Mathematics
2 answers:
klemol [59]3 years ago
6 0
I think its 91. hope this helps


Paul [167]3 years ago
5 0
I think its 91.

NOT Guaranteed this is the Answer. Best of luck to you.
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If y varies directly as x, and y is 400 when x is randy is r when x is 4, what is the numeric constant of variation in this rela
juin [17]

The numeric constant of variation is 100

Step-by-step explanation:

Direct proportion means that increase in one variable cause increase in other variable

Here,

It is given that

y varies directly as x

y∝x

when the proportionality symbol is removed a proportionality constant is introduced

y = kx

Given that

y = 100 when x = 4

Putting the values

400 = k * 4\\k = \frac{400}{4}\\k = 100

The numeric constant of variation is 100

Keywords: Proportion variation

Learn more about direct proportion at:

  • brainly.com/question/1234767
  • brainly.com/question/1232765

#LearnwithBrainly

5 0
3 years ago
Someone please help me
lutik1710 [3]

Answer:

18

Step-by-step explanation:

I did that in my head could be wrong

3 0
3 years ago
The net of a triangular prism and its dimensions are shown below. What is the total surface area of the prism? a) 54 m squared b
Andre45 [30]

Answer:

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✅ I will have the file for the answer key below!

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Download pdf
4 0
2 years ago
Read 2 more answers
PLZ HELP ANSWER AND EXPLAIN. (photo) #8
evablogger [386]
The picture shown is a unfolded rectangular prism.

The formula to find the surface area of a rectangular prism is:

A = 2(WL+HL+HW)

(W = width, L = Length, H= Height)

So we would need to determine the Height, Length, and Width first, and then plug them into the formula and solve for the area.

In this case:
The height is: 4 cm 
The length is: 10.5 cm
The width is: 6.4 cm

Now that we have determined the height, length, and width, we simply plug them into the formula I showed earlier. 

In this case the answer would be 269.6.

D. 269.6
8 0
2 years ago
Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal
Usimov [2.4K]

Answer:

a) We have that the significance is given by \alpha =0.01 and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case z_{crit}=2.33

So then the rejection region would be z>2.33

b) We have that the significance is given by \alpha =0.05, \alpha/2 =0.025 and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case z_{crit}=\pm 1.96

So then the rejection region would be z>1.96 \cup z

Step-by-step explanation:

Part a

We have that the significance is given by \alpha =0.01 and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case z_{crit}=2.33

So then the rejection region would be z>2.33

Part b

We have that the significance is given by \alpha =0.05, \alpha/2 =0.025 and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case z_{crit}=\pm 1.96

So then the rejection region would be z>1.96 \cup z

7 0
3 years ago
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