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hodyreva [135]
3 years ago
13

Which shape has opposite sides that are both equal in length and parallel and always has four right angles? A. triangle B. recta

ngle C. pentagon D. parallelogram
Mathematics
1 answer:
ra1l [238]3 years ago
8 0
I think its b
hope this helps
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How many different triangles can be constructed with three sides, each measuring 5 centimeters?
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Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

\sf\longrightarrow sin^2\theta + cos^2\theta = 1

Imagine a right angled triangle with one of its acute angle as \theta .

  • The side opposite to this angle will be perpendicular .
  • Also we know that ,

\sf\longrightarrow sin\theta =\dfrac{p}{h} \\

\sf\longrightarrow cos\theta =\dfrac{b}{h}

And by Pythagoras theorem ,

\sf\longrightarrow h^2 = p^2+b^2 \dots (i)

Where the symbols have their usual meaning.

Now , taking LHS ,

\sf\longrightarrow sin^2\theta +cos^2\theta

  • Substituting the respective values,

\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\

\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\

\sf\longrightarrow \dfrac{p^2+b^2}{h^2}

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\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\

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Since LHS = RHS ,

Hence Proved !

I hope this helps.

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