I assume
has counterclockwise orientation when viewed from above.
By Stokes' theorem,

so we first compute the curl:


Then parameterize
by

where the
-component is obtained from

with
and
.
Take the normal vector to
to be

Then the line integral is equal in value to the surface integral,



The answer is 46°.
The measure of an inscribed angle is equal to (1/2) the measure of the intercepted arc.
That means that, since ADC is 23 degrees, doubling that gives you 46 degrees, the measure of the intercepted arc.
Central angles are equal to the measure of the intercepted arc, which in this case is the same arc we just calculated.
Therefore it's 46.
The slope is -2. this is because if you look at the graph it goes down 2 units and it goes right to the once so it’ll be -2/1 which equals -2.
Answer:
C. 101 - 5(n - 1)
Step-by-step explanation:
d = (26 - 71)/(16 - 7)
d = -45/9
d = -5
a7 = a1 + (7-1)(-5)
71 = a1 - 30
a1 = 101
an = 101 + (n - 1)(-5)
an = 101 - 5(n - 1)
.....................................