When the molar mass M = mass (g)/ no.of moles (Mol)
∴ moles= 0.271 g / M
By using the gas equation:
PV = n RT
when P is the pressure = 847 mmHg / 760 = 1.11 atm
V is the volume = 0.294 L
n = 0.271 / M
R is constant = 0.0821
T= 140+273 = 413 K
so by substitution:
when n = PV/RT
∴ 0.271/ M = 1.11 atm *0.294 L/ 0.0821 *413
∴ M = 28
when the empirical formula of CH2 = 12+2 = 14
∴ the exact no.of moles = 28/14 = 2
∴the molecular formula = 2(CH2) = C2H4
Lesser. atomic number means proton number
The equation representing the decomposition of BaCO₃ is as follow:
BaCO₃(s) ⇄ BaO(s) + CO₂(g)
Standard Gibbs-free energy (ΔG⁰) = 220 kJ/mol
Gas constant (R) = 8.314 x 10⁻³ kJ/K.mol
Temperature (T) =25 + 273 = 298 K
ΔG⁰ = - R T lnK
ln K = - ΔG⁰ / RT = - 88.8
K =
![e^{-88.8}](https://tex.z-dn.net/?f=%20e%5E%7B-88.8%7D%20)
= 2.7 x 10⁻³⁹
So the equilibrium constant of the reaction at 298 K is 2.7 x 10⁻³⁹
From the equation:
Equilibrium constant Kp = Pco₂
![P_{CO_{2}}](https://tex.z-dn.net/?f=%20P_%7BCO_%7B2%7D%7D%20)
= 2.7 x 10⁻³⁹ atm
Answer: option B - 2 K + MgBr2 = 2 KBr + Mg
Explanation:
2K + MgBr2 --> 2 KBr + Mg
On Left side: 2moles of Potassium (K) reacts with 1 mole of MgBr2
On Right side: 2 moles of KBr and 1 mole of Mg.
You will observe that the coefficient of each element on left side and Right side is balanced in option B, unlike other options.
So, option B is the answer.
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