Which element has similar chemical properties compared to Carbon (C)?

Which cell has the better survival plan, animal or plant cell? Support your answer with facts I WILL GIVE BRAINLIEST ANSWER

d1i1m1o1n [39]

If im not mistaken plant cells go through a stage called photosynthesis meaning the cells can create it's own energy (food) off of water, Co2 and sunlight.

7 0

3 years ago

When Earth receives energy from the Sun, ____. a. some energy is reflected back into space b. some is absorbed by the atmosphere

Triss [41]

Answer:

D - all of the above

Explanation:

5 0

1 year ago

If the neutral solution was boiled to dryness, what would be the formula of the resulting salt.

mash [69]

Answer:

Forumula

XOH + HY = XY + H2O

Explanation:

Salt formed from: Salt Solution

Strong acid + Strong base Neutral

Strong acid + Weak base Acidic

Weak acid + Strong base Basic

Neutral solution example

NaCl = Sodium chloride

HCl = H+ and Cl-

NaOH = Na+ and OH-

OH- = Strong Base

H+ = Strong Acid

Sodium chloride, formed from neutralization of HCl by NaOH.

NaOH + HCl = NaCl + H2O

NaCl in water is not acidic or basic, since it's ions cannot hydrolyze.

So formula would be XOH + YH = XY + H2O

7 0

2 years ago

Consider the reaction 2CO(g) + O2(g)2CO2(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surr

Marizza181 [45]

Answer: The value of $\Delta S^o$ for the surrounding when given amount of CO is reacted is 432.52 J/K

Explanation:

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$2CO(g)+O_2(g)\rightarrow 2CO_2(g)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(CO_2(g))})]-[(1\times \Delta S^o_{(O_2(g))})+(2\times \Delta S^o_{(CO(g))})]$

We are given:

$\Delta S^o_{(CO_2(g))}=213.74J/K.mol\\\Delta S^o_{(O_2)}=205.14J/K.mol\\\Delta S^o_{(CO)}=197.674J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (213.74))]-[(1\times (205.14))+(2\times (197.674))]\\\\\Delta S^o_{rxn}=-173.008J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-173.008) J/K = 173.008 J/K

We are given:

Moles of CO gas reacted = 2.25 moles

By Stoichiometry of the reaction:

When 2 moles of CO is reacted, the entropy change of the surrounding will be 173.008 J/K

So, when 2.25 moles of CO is reacted, the entropy change of the surrounding will be = $\frac{173.008}{1}\times 2.25=432.52J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of CO is reacted is 432.52 J/K

3 0

3 years ago

The CO2 produced in one round of the citric acid cycle does not originate in the acetyl carbons that entered that round. If the

aleksley [76]

Answer:

It will require second round of the cycle to release $14C0_2$

Explanation:

Reason behind the requirement of second round of the cycle to release $CO_2$ -:

The C4 carbon of succinyl CoA is acetyl from acetyl CoA. Succinyl CoA is converted to succinate, which is then converted to fumarate, fumarate, malate, and eventually oxaloacetate. 14C will be found in oxaloacetate at either C1 or C4. During the second round of the loop, each of these carbons will be converted to carbon dioxide.

7 0

2 years ago