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3 years ago

Recognizing the Properties of Water

Chemistry

2 answers:

jok3333 [9.3K]3 years ago

7 0

Answer:

1. c

2.b

Explanation:

Sholpan [36]3 years ago

6 0

The first option does explain waters bent geometry. The Oxygen atom in water has two pairs of unbonded electrons. They are repelling each other. Water can form hydrogen bonds due to the electron distribution not the geometry. However the last statement is more untrue. Electrons are drawn to the more electronegative atom which is oxygen so that where they spend the most time.

Therefore the last one being untrue does not explain the geometry.

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2 years ago

If you feed 100 kg of N2 gas and 100 kg of H2 gas into a

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Answer : The mass of ammonia produced can be, 121.429 k

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First we have to calculate the moles of $N_2$ and $H_2$ .

$\text{ Moles of }N_2=\frac{\text{ Mass of }N_2}{\text{ Molar mass of }N_2}=\frac{100000g}{28g/mole}=3571.43moles$

$\text{ Moles of }H_2=\frac{\text{ Mass of }H_2}{\text{ Molar mass of }H_2}=\frac{100000g}{2g/mole}=50000moles$

Now we have to calculate the limiting and excess reagent.

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From the balanced reaction we conclude that

As, 1 mole of $N_2$ react with 3 mole of $H_2$

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From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $N_2$ is a limiting reagent and it limits the formation of product.

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From the reaction, we conclude that

As, 1 mole of $N_2$ react to give 2 mole of $NH_3$

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Now we have to calculate the mass of $NH_3$

$\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3$

$\text{ Mass of }NH_3=(7142.86moles)\times (17g/mole)=121428.62g=121.429kg$

Therefore, the mass of ammonia produced can be, 121.429 kg

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