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AfilCa [17]
3 years ago
9

The distance from the crest of a wave to the next crest is 10 centimeters. The distance from a crest of this wave to a trough is

4 centimeters. A)what is the amplitude of this wave? B)what is the wavelength of this wave?
Physics
2 answers:
Sliva [168]3 years ago
6 0
It's  A what is the amplitude of this wave i think 
marissa [1.9K]3 years ago
5 0
Its B for sure. it sucks that we have to right at least 20 letters each question we answer




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Kinetic and potential; what type of energy is each of the points
miskamm [114]

Answer:

1 potential

2 kenitic

3 kenitic

4 potential

5 kenitic

6 potential

7 0
4 years ago
Water flows from the bottom of a storage tank at a rate of r(t) = 300 − 6t liters per minute, where 0 ≤ t ≤ 50. Find the amount
SSSSS [86.1K]

r(t) models the water flow rate, so the total amount of water that has flowed out of the tank can be calculated by integrating r(t) with respect to time t on the interval t = [0, 35]min

∫r(t)dt, t = [0, 35]

= ∫(300-6t)dt, t = [0, 35]

= 300t-3t², t = [0, 35]

= 300(35) - 3(35)² - 300(0) + 3(0)²

= 6825 liters

7 0
3 years ago
Due today HELP HELP HELP
Anna [14]

Vas happenin!

Independent variable : amount of water each day

Dependent variable: water on the windsill

Hypotheses: Ben wants to try by adding water each day to two different places. Will that work? Will that effect the water?


Hope this helps you out

*smiles*


-Zayn Malik
5 0
3 years ago
Brainliest if correct Question 10 of 10
11Alexandr11 [23.1K]

Answer:

D thermal energy moves from the marshmallow to your fingers as you touch the marshmallow

Explanation:

Conduction is the movement of thermal energy without the actual movement of the particles of a body. They particles only collide with each other and transfer energy in the process while maintaining their mean positions.

5 0
2 years ago
Read 2 more answers
A 1.0-kg ball is attached to the end of a 2.5-m string to form a pendulum. This pendulum is released from rest with the string h
hram777 [196]

Answer:

v_{2}=3.5 m/s

Explanation:

Using the conservation of energy we have:

\frac{1}{2}mv^{2}=mgh

Let's solve it for v:

v=\sqrt{2gh}

So the speed at the lowest point is v=7 m/s

Now, using the conservation of momentum we have:

m_{1}v_{1}=m_{2}v_{2}

v_{2}=\frac{1*7}{2}

Therefore the speed of the block after the collision is v_{2}=3.5 m/s

I hope it helps you!

       

8 0
3 years ago
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