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tatiyna
3 years ago
9

What are scientists who study space called?

Physics
2 answers:
ikadub [295]3 years ago
7 0

`•.,¸¸,.•´¯     '     ¯´•.,¸¸,.•`

Answer:

Brilliant_brown [7]3 years ago
4 0

Answer:

Astronomer

Explanation:

A scientist who studies the objects in the sky, including planets, galaxies, black holes, and stars, is called an astronomer. These days, the terms astronomer and astrophysicist are used interchangeably, to talk about any physicist who specializes in celestial bodies and the forces that affect them.

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Which is the most important factor in determining climate?
Leokris [45]

Answer:

B took the test (k12)

Explanation:

6 0
3 years ago
A mass weighting 48 lbs stretches a spring 6 inches. The mass is in a medium that exerts a viscous resistance of 27 lbs when the
Mademuasel [1]

Answer:

a)

u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)

b)

m = 48lb

c)

b = 144.76lb

Explanation:

The general equation of a damping oscillate motion is given by:

u(t)=u_oe^{-\frac{b}{2m}t}cos(\omega t-\alpha)    (1)

uo: initial position

m: mass of the block

b: damping coefficient

w: angular frequency

α: initial phase

a. With the information given in the statement you replace the values of the parameters in (1). But first, you calculate the constant b by using the information about the viscous resistance force:

|F_{vis}|=bv\\\\b=\frac{|F_{vis}|}{v}\\\\|F_{vis}|=27lbs=27*32.17ft.lb/s^2=868.59ft.lb/s^2\\\\b=\frac{868.59}{6}lb/s=144.76lb/s

Then, you obtain by replacing in (1):

6in = 0.499 ft

u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)

b.

mass, m = 48lb

c.

b = 144.76 lb/s

8 0
3 years ago
A puck sliding on ice approaches a 20 degrees ramp at 10 m/s with coefficient of friction 0.2. How high will it go up the ramp a
timama [110]

Answer:

it will go up along the inclined plane by d = 9.62 m

Explanation:

As we know that puck is moving upward along the slide

then the net force opposite to its speed is given as

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so here deceleration is given as

a = -g(sin\theta + \mu cos\theta)

now plug in all values in it

a = -9.81(sin20 + 0.2cos20)

a = -5.2 m/s^2

now the distance covered by the puck along the plane is given as

v_f^2 - v_i^2 = 2 a d

0 - 10^2 = 2(-5.2)d

d = 9.62 m

3 0
4 years ago
A ball is kicked horizontally at 10.0 m/s from a cliff 100m high. How far from the base of the cliff will the stone strike the g
Black_prince [1.1K]

bggdgggxccc

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jrhvbjgvbjvgbh

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An electroscope is a device that has small gold foil strips suspended from a metal rod. A student brings a negatively charged ro
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