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2 years ago

Distance from any point on a wave to an identical point on the next wave?

1 answer:

6 0

It's called the "Wavelength". It corresponds to <span>the distance from any point on a wave to an identical point on the next wave and could also be from crest to crest or trough to trough.

Hope this helps !

Photon</span>

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Which of the following types of energy is not associated with a car engine?

soldi70 [24.7K]

Answer:

Explanation:

Does not assosicate with Light

4 0

2 years ago

At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1515

Talja [164]

Complete Question

At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1/5.

Answer:

The angle is

Explanation:

From the question we are told that

The light emerging from second Polaroid is 1/5 the unpolarized

Generally the intensity of light emerging from the first Polaroid is mathematically represented as

$I_1 = \frac{I_o}{ 2 }$

Generally from the Malus law the intensity of light emerging from the second Polaroid is mathematically represented

$I_2 = I_1 cos^2 (\theta )$

=> $cos^2 (\theta ) = \frac{I_2}{I_1 }$

=> $cos (\theta) = \sqrt{ \frac{I_2}{I_1} }$

From the question $I_2 = \frac{I_o}{5}$

$cos (\theta) = \sqrt{ \frac{ \frac{ I_o}{5} }{\frac{I_o}{2} } }$

$cos (\theta) = \sqrt{ \frac{2}{5} }$

=> $\theta = cos ^{-1} [\sqrt{\frac{2}{5}} ]$

=> $\theta = 50.77^o$

8 0

3 years ago

What is the momentum of a helicopter of mass 200 kg moving with a speed of 3 m/s?

omeli [17]

Answer: 600

200 times 3 = 600

7 0

3 years ago

Using the graph, predict how many paper clips a 7.5 V battery would pick up for both the 25-coil electromagnet and the 50-coil e

insens350 [35]

Data:
25 turn electromagnet
batter voltage: 1.5 V , 3.0 V , 4.5 V, 6.0V
paper clips picked up first try: 5, 12, 14, 20
paper clips picked up second try: 7, 12, 17, 26
average: 6, 12, 15.5, 23

50 turn electromagnet
battery voltage: 1.5 V, 3.0 V, 4.5 V, 6.0 V
paperclips picked up first try: 10, 28, 30, 44
paperclips picked up second try: 16, 24, 32, 50
average: 13, 26, 31, 47

8 0

2 years ago

0.5000 kg of water at 35.00 degrees Celsius is cooled, with the removal of 6.300 E4 J of heat. What is the final temperature of

MArishka [77]

Answer:

65.1 °C

Explanation:

m = mass of the water = 0.5 kg

$T_{i}$ = initial temperature of water = 35.00 °C

$T_{f}$ = final temperature of water

c = specific heat of water = 4186 J/(kg °C)

Q = Amount of heat removed from water = 6.3 x 10⁴ J

Amount of heat removed from water is given as

Q = m c ( $T_{f}$ - $T_{i}$ )

Inserting the values

6.3 x 10⁴ = (0.5) (4186) ( $T_{f}$ - 35.00)

$T_{f}$ = 65.1 °C

5 0

3 years ago

Read 2 more answers