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3 years ago

Answer the question correctly. Look at the 2 pictures.

Physics

2 answers:

guajiro [1.7K]3 years ago

7 0

3.15
Hope it helped!!

Alexxandr [17]3 years ago

4 0

Answer:

The answer is 3.15

Explanation:

I added lol

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Look at the diagram showing resistance and flow of electrons.

poizon [28]

The answer would be:

X: Low potential energy

Y: High Potential energy

Z: Flow of electrons

Z is clearly the flow of electrons, as shown by the arrow demonstrating the direction of the flow. So you can easily cross out choices B and C. Now, you can see that Y has more energy stored and X has a lot less, so you can conclude that Y has high potential energy while X has low potential energy.

8 0

3 years ago

Read 2 more answers

A 14.0 g wad of sticky clay is hurled horizontally at a 110 g wooden block initially at rest on a horizontal surface. The clay s

ahrayia [7]

Answer:

86.53 m/s

Explanation:

Given:

Mass of clay (m) = 14.0 g = 0.014 kg

Mass of block (M) = 110 g = 0.110 kg

Initial speed of block (U) = 0 m/s

Sliding distance (d) = 7.50 m

Coefficient of friction between block and surface (μ) = 0.650

Let the initial speed of clay be 'u' and speed of clay and block just after collision be 'v'.

Now, momentum is conserved just before and just after collision.

Momentum just before collision = $mu + 0 = mu$

Momentum just after collision = $(m + M)v$

Therefore, $mu=(M+m)v$ --------- (1)

Now, using newton's second law and we find the acceleration of the system.

The frictional force is given as:

$f=\mu mg=-ma\\\\a=-\mu g$

Now, using equation of motion, we can find the velocity just after collision.

$0^2=v^2+2ad\\\\v=\sqrt{-2ad}\\\\v=\sqrt{-2\times (-\mu g)\times d}\\\\v=\sqrt{2\mu gd}$

Plug in the given values and find 'v'. This gives,

$v=\sqrt{2\times 0.650\times 9.8\times 7.50}\\\\v=\sqrt{95.55}=9.77\ m/s$

Now, using equation (1) and substituting the given values, we get:

$0.014u=(0.014+0.110)\times 9.77\\\\u=\frac{0.124\times 9.77}{0.014}\\\\u=86.53\ m/s$

Therefore, the speed of the clay immediately before impact is 86.53 m/s.

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4 years ago

How dose an exam question outed from text book

Verizon [17]

Answer:

In which school you are???

Explanation:

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3 years ago

This graph shows a ball rolling from A to G. The ball starts at point A and rolls to point G.

Lerok [7]

11. B

12. A

13. D

14. The ball burnt off energy while rolling, it lost potential energy and couldn't go as high.

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3 years ago

A plastic rod that has been charged to -21 nc touches a metal sphere. afterward, the rod's charge is -8 nc. (a) what kind of cha

otez555 [7]

The rod transferred negatively charged particle to the metal sphere. The rod becomes less negatively charged than it was originally (originally it was charged to -21 nc, now it has -8, and -8>-21), so it must have moved 13 nc of negative charge to the sphere.

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4 years ago