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Sunny_sXe [5.5K]
3 years ago
15

What is a tension force

Physics
1 answer:
hoa [83]3 years ago
6 0

Explanation:

tension is described as the pulling force transmitted axially by the means of a string, a cable, chain, or similar one-dimensional continuous object, or by each end of a rod, truss member, or similar three-dimensional object.

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Which technique is the most useful for measuring the distance to a galaxy located 10 million light-years away?
devlian [24]

The technique which is the most useful for measuring the distance to a galaxy located 10 million light-years away is Cepheids

A Cepheid variable is a particular kind of star that pulses radially, varying in diameter and temperature while causing changes in brightness with a clearly discernible steady time and amplitude.

A light-year is defined as the total amount of distance covered by light in a year. It is usually a unit to measure very large distances which usually concerns the Outerspace

A galaxy is a system made up of stars, stellar debris, interstellar gas, dust, and other matter that is gravitationally bound. The name "galaxy" is derived from the Greek word "galaxies," which is an allusion to the Milky Way and literally means "milky."

Learn more about Cepheids here

brainly.com/question/15182908

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7 0
2 years ago
In a football game a kicker attempts a field goal. The ball remains in contact with the kicker's foot for 0.0580 s, during which
Fantom [35]

Answer:

V₀ₓ = 10.94 m/s

V₀y = 18.87 m/s

Explanation:

To find the launch velocity, we use 1st equation of motion.

Vf = Vi + at

where,

Vf = Final Velocity of Ball = Launch Speed = V₀ = ?

Vi = Initial Velocity = 0 m/s (Since ball was initially at rest)

a = acceleration = 376 m/s²

t = time = 0.058 s

Therefore,

V₀ = 0 m/s + (376 m/s²)(0.058 s)

V₀ = 21.81 m/s

Now, for x-component:

V₀ₓ = V₀ Cos θ

where,

V₀ₓ = x-component of launch velocity = ?

θ = Angle with horizontal = 59.9⁰

V₀ₓ = (21.81 m/s)(Cos 59.9°)

<u>V₀ₓ = 10.94 m/s</u>

<u></u>

for y-component:

V₀ₓ = V₀ Sin θ

where,

V₀y = y-component of launch velocity = ?

θ = Angle with horizontal = 59.9⁰

V₀y = (21.81 m/s)(Sin 59.9°)

<u>V₀y = 18.87 m/s</u>

<u></u>

8 0
4 years ago
A 100 kg mass is pulled along a frictionless surface by a horizontal force F such that its acceleration is 8.0 m/s2. A 20 kg mas
nadya68 [22]

Answer:

a) 60 N

b) 860 N

Explanation:

Given that,

m_1 = 100 kg

m_2 = 20 kg

a_{1} = 8.0 \frac{m}{s^{2}}

a_{2} = 3.0 \frac{m}{s^{2}}

a) By Newton's Law,

∑F_{m_2,x} = f_k = m_{2} * a_{2}

∑F_{m_2,y} = F_{N} - m_{2} * g = 0

Hence,

f_k = m_2 * a_2 = 20 * 3 = 60 N

b) By Newton's Law

∑F_{m_1,x} = F = m_{1} * a_{1}

Hence,

F = m_{1} * a_{1} = 100 * 8 = 800 N

Net force acting on 100 kg mass,

F_{net} = F + f_k = 800 + 60 = 860 N

6 0
3 years ago
A car is traveling at a speed of 50 km/hr. The positive y-axis is north and the positive x-axis is east. Resolve the car's veloc
hjlf
We need to draw a coordinates. the east and south should be the north vector for horizontal line 50 KM in distance is zero. the south is a negative. the south east and north west we should draw the 45 degrees angle in the approprate quadrant and then use the 1-1-sqrt(2) have a relationship in 45-45-90 triangles to resolve the N/S, E/W components.

hope this help
6 0
3 years ago
The broad, slightly dome-shaped volcanoes of Hawaii are___.
Dafna11 [192]
The broad, slightly dome-shaped volcanoes of Hawaii are sheild volcanoes
4 0
3 years ago
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