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Law Incorporation [45]
3 years ago
7

True or False: The average speed of an object is always equal to the magnitude of the average velocity of the object. If False,

then give an example of motion where this is false. If True, then explain why.
Physics
1 answer:
yuradex [85]3 years ago
4 0

Answer:

Explanation:

Average speed is defined as the ratio of total distance to the total time taken. It is a scalar quantity.

Average velocity is defined as the total displacement to the total time taken. It is a vector quantity.

They both are equal, if the motion is straight line.

So, every time it is not true.

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Klio2033 [76]

Answer:

not sure

Explanation:

jahhhhhsjjjjdddddhdhdj hbdbd#dialectical DHL I have no clue W Bush administration and I don't have any jshshhhhdgggddddddd the entire community was literate because

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a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

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a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

jsbsbd the entire community was literate because

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c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

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BFF and I don't have any questions please call her and her husband to the hospital for a bit more time with my family grew up in the form of a ring whose inner circumference is it a lot of people who are you doing today beautiful and I don't have any questions please call her and her husband to the

4 0
3 years ago
Approximately _____ of those who suffer from anorexia nervosa literally starve themselves to death.
Vadim26 [7]
Appproximately 10% of those who suffer from anorexia nervosa literally starve themselves to death.
6 0
3 years ago
What must be the distance between point charge 91 = 20 MC and point charge 02 -45,0 AC for the electrostatic force between them
Fynjy0 [20]

Answer:

Explanation:

Q₁ = 20 X 10⁻⁶ C

Q₂ = -45 X 10⁻⁶ C

d is required distance.

F = Force between the = 7 N

F = k x Q₁ X Q₂ / d²

d² = k x Q₁ X Q₂ / F = 20 X 45 X 10⁻¹² X 9 X 10⁹  /7

=1.157

d = 1.075 m

7 0
3 years ago
Write .00000023 in scientific notation
Vikki [24]

Answer: 2.3 x 10^-7

Explanation:

When you move the decimal to the right, you decrease the exponent. So lets count how many spots you have to move the decimal spot to get an answer between 1 and 10. I counted seven spots.

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2.3 *10^-^7

8 0
3 years ago
Read 2 more answers
The crate, which sets on a 10 degree incline, has a weight of 3433.5 N and is subjected to a towing force P acting at a 20 degre
sp2606 [1]

Answer:

P = 981 N

Explanation:

Given

Angle of the incline θ = 10°

Angle of the towing force φ =20°

Weight of the crate W = 3433.5 N

The coefficient of static friction µ = 0.5

Solution

Forces Acting along the ramp

\mu N = Pcos(10^{o}+10^{o})+Wsin10^{0} \\\mu N = Pcos30^{o}+Wsin10^{0}

Forces acting perpendicular to the ramp

N + Psin30^{o}=Wcos10^{0}\\\\N=Wcos10^{0}-Psin30^{o}\\

Substituting the value of N we get

\mu[Wcos10^{0}-Psin30^{o}] =Pcos30^{o}+Wsin10^{0}\\\\\mu Wcos10^{0}- \mu Psin30^{o} =Pcos30^{o}+Wsin10^{0}\\\\\mu Wcos10^{0}- Wsin10^{0}=Pcos30^{o}+\mu Psin30^{o} \\\\P=W\frac{\mu cos10^{0}- sin10^{0}}{cos30^{o}+\mu sin30^{o}} \\\\P=3433.5\frac{0.5 \times cos10^{0}- sin10^{0}}{cos30^{o}+0.5 \times  sin30^{o}}\\\\P=980.66\\\\ P = 981 N

6 0
3 years ago
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